“NSLinguisticTag”类型的值没有成员“范围”

Sam*_*Sam 3 swift nslinguistictagger swift4

我有文本方向代码,它在 swift 3 中运行良好,但在迁移到 swift 4 后,我收到错误

let tagScheme = [NSLinguisticTagScheme.language]
    let tagger    = NSLinguisticTagger(tagSchemes: tagScheme, options: 0)
    tagger.string = self.text
    let lang      = tagger.tag(at: 0, scheme: NSLinguisticTagScheme.language,
                                      tokenRange: nil, sentenceRange: nil)

    if lang?.range(of: "he") != nil ||  lang?.range(of: "ar") != nil { //Value of type 'NSLinguisticTag' has no member 'range' 
        self.textAlignment = NSTextAlignment.right
    } else {
        self.textAlignment = NSTextAlignment.left
    }
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有人知道怎么修这个东西吗?谢谢

Mar*_*n R 5

从 Swift 4 开始,NSLinguisticTagger标签不是作为(可选)字符串返回,而是作为(可选)值返回NSLinguisticTag

public struct NSLinguisticTag : RawRepresentable, Equatable, Hashable {
    public init(_ rawValue: String)
    public init(rawValue: String)
}
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您将获得具有以下rawValue属性的基础字符串:

 if let lang = tagger.tag(at: 0, scheme: .language, tokenRange: nil, sentenceRange: nil) {
    print(lang.rawValue)
    if lang.rawValue.hasPrefix("he") { ... }
}
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如果您想检查相等性而不是包含性,那么您还可以定义自己的NSLinguisticTag常量:

extension NSLinguisticTag {
    static let hebrew = NSLinguisticTag("he")
}
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并将它们用作

if let lang = tagger.tag(at: 0, scheme: .language, tokenRange: nil, sentenceRange: nil) {
    if lang == .hebrew { ... }
}
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另一种选择是定义自定义计算属性

extension NSLinguisticTag {
    var isRightToLeft: Bool {
        return rawValue.hasPrefix("he") || rawValue.hasPrefix("ar")
    }
}
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并将其用作

if let lang = tagger.tag(at: 0, scheme: .language, tokenRange: nil, sentenceRange: nil) {
    if lang.isRightToLeft { ... }
}
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