ℕʘʘ*_*ḆḽḘ 12 r ggplot2 dplyr tidyeval
考虑这个简单的例子
library(dplyr)
library(ggplot2)
dataframe <- data_frame(id = c(1,2,3,4),
group = c('a','b','c','c'),
value = c(200,400,120,300))
# A tibble: 4 x 3
id group value
<dbl> <chr> <dbl>
1 1 a 200
2 2 b 400
3 3 c 120
4 4 c 300
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在这里,我想编写一个将数据帧和分组变量作为输入的函数.理想情况下,在分组和聚合后,我想打印一个ggpplot图表.
这有效:
get_charts2 <- function(data, mygroup){
quo_var <- enquo(mygroup)
df_agg <- data %>%
group_by(!!quo_var) %>%
summarize(mean = mean(value, na.rm = TRUE),
count = n()) %>%
ungroup()
df_agg
}
> get_charts2(dataframe, group)
# A tibble: 3 x 3
group mean count
<chr> <dbl> <int>
1 a 200 1
2 b 400 1
3 c 210 2
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不幸的是,添加ggplot到FAILS上面的功能
get_charts1 <- function(data, mygroup){
quo_var <- enquo(mygroup)
df_agg <- data %>%
group_by(!!quo_var) %>%
summarize(mean = mean(value, na.rm = TRUE),
count = n()) %>%
ungroup()
ggplot(df_agg, aes(x = count, y = mean, color = !!quo_var, group = !!quo_var)) +
geom_point() +
geom_line()
}
> get_charts1(dataframe, group)
Error in !quo_var : invalid argument type
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我不明白这里有什么问题.有任何想法吗?谢谢!
编辑:这里有趣的后续如何使用ggplot和dplyr从函数中的quosures创建因子变量?
MrF*_*ick 12
ggplot还不支持整洁的eval语法(你不能使用!!).您需要使用更传统的标准评估调用.您可以aes_q在ggplot 中使用它来帮助解决这个问题.
get_charts1 <- function(data, mygroup){
quo_var <- enquo(mygroup)
df_agg <- data %>%
group_by(!!quo_var) %>%
summarize(mean = mean(value, na.rm = TRUE),
count = n()) %>%
ungroup()
ggplot(df_agg, aes_q(x = quote(count), y = quote(mean), color = quo_var, group = quo_var)) +
geom_point() +
geom_line()
}
get_charts1(dataframe, group)
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ggplot2 v3.0.02018年7月发布的支持!!(bang bang)!!!,和:=.aes_()/aes_q()并且aes_string()软弃用.
OP的原始代码应该有效
library(tidyverse)
get_charts1 <- function(data, mygroup){
quo_var <- enquo(mygroup)
df_agg <- data %>%
group_by(!!quo_var) %>%
summarize(mean = mean(value, na.rm = TRUE),
count = n()) %>%
ungroup()
ggplot(df_agg, aes(x = count, y = mean,
color = !!quo_var, group = !!quo_var)) +
geom_point() +
geom_line()
}
get_charts1(dataframe, group)
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由reprex包(v0.2.0)创建于2018-04-04.