Bil*_*ler 6 python colors matplotlib pandas seaborn
我试图用两个图创建一个子图。第一个图实质上是散点图(我正在使用regplot),第二个图是直方图。
我的代码如下:
import pandas as pd
import matplotlib.pyplot as plt
import seaborn as sns
data = {'source':['B1','B1','B1','C2','C2','C2'],
'depth':[1,4,9,1,3,10],
'value':[10,4,23,78,24,45]}
df = pd.DataFrame(data)
f, (ax1, ax2) = plt.subplots(1,2)
for source in df['source'].unique():
x = df.loc[df['source'] == source, 'value']
y = df.loc[df['source'] == source, 'depth']
sns.regplot(x,
y,
scatter = True,
fit_reg = False,
label = source,
ax = ax1)
ax1.legend()
sns.distplot(x,
bins = 'auto',
norm_hist =True,
kde = True,
rug = True,
ax = ax2,
label = source)
ax2.legend()
ax2.relim()
ax2.autoscale_view()
plt.show()
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结果如下所示。
如您所见,散点图和直方图之间的颜色是不同的。现在,我在玩各种颜色的托盘,但都没有用。谁能阐明我如何同步颜色?
谢谢。
使用color绘图函数的参数。在这个例子中,你的 for 循环中当前的 seaborn 调色板与itertools.cycle要绘制的颜色是一一选择的:
import pandas as pd
import matplotlib.pyplot as plt
import seaborn as sns
import itertools
data = {'source':['B1','B1','B1','C2','C2','C2'],
'depth':[1,4,9,1,3,10],
'value':[10,4,23,78,24,45]}
df = pd.DataFrame(data)
f, (ax1, ax2) = plt.subplots(1,2)
# set palette
palette = itertools.cycle(sns.color_palette())
# plotting
for source in df['source'].unique():
x = df.loc[df['source'] == source, 'value']
y = df.loc[df['source'] == source, 'depth']
# color
c = next(palette)
sns.regplot(x,
y,
scatter = True,
fit_reg = False,
label = source,
ax = ax1,
color=c)
ax1.legend()
sns.distplot(x,
bins = 'auto',
norm_hist =True,
kde = True,
rug = True,
ax = ax2,
label = source,
color=c)
ax2.legend()
ax2.relim()
ax2.autoscale_view()
plt.show()
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