Jie*_*eng 5 zend-framework zend-acl zend-controller-plugin
我想知道使用Zend_Acl显示/隐藏部分视图的方式是什么?我想我会的
创建一个Controller插件,用于将登录的用户+ acl传递给视图
$this->view->loggedInUser = Zend_Auth::getIdentity();
$this->view->acl = Zend_Registry::get('acl');
Run Code Online (Sandbox Code Playgroud)然后在视图脚本中做类似的事情
$this->acl->isAllowed($this->view->loggedInUser, 'resource', 'privilege');
Run Code Online (Sandbox Code Playgroud)或者,还有更好的方法?或者我应该使用View Helper?返回一个布尔值是否允许登录用户?
您在视图中使用它,所以对我来说 ViewHelper 是正确的位置 - 我已经这样做过一次:
class Zend_View_Helper_HasAccess extends Zend_View_Helper_Abstract
{
private $_acl;
public function hasAccess($role, $controller, $action)
{
if (!$this->_acl) {
$this->_acl = Zend_Controller_Front::getInstance()->getPlugin('Acl');
//In yout case registry, but front controller plugin is better way to implement ACL
}
return $this->_acl->isAllowed($role, $controller, $action);
}
}
Run Code Online (Sandbox Code Playgroud)