根据键名将大型数组拆分为较小的数组

Question

我有下面的数组,我需要根据[location]键拆分成更小的数组(所以我想要一个.co.uk数组和一个.com数组).[location]键不限于.co.uk或.com.

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[22] => Array
    (
        [query] => tttt
        [location] => .co.uk
        [x] => 1292889600
        [y] => 1
        [fullurl] => http://www.tttt.com/
    )

[20] => Array
    (
        [query] => tttt
        [location] => .co.uk
        [x] => 1292976000
        [y] => 1
        [fullurl] => http://www.tttt.com/
    )

[21] => Array
    (
        [query] => tttt
        [location] => .com
        [x] => 1292976000
        [y] => 1
        [fullurl] => http://www.tttt.com/
    )

[19] => Array
    (
        [query] => tttt
        [location] => .co.uk
        [x] => 1293062400
        [y] => 1
        [fullurl] => http://www.tttt.com/
    )

[18] => Array
    (
        [query] => tttt
        [location] => .com
        [x] => 1293062400
        [y] => 1
        [fullurl] => http://www.tttt.com/
    )

[17] => Array
    (
        [query] => tttt
        [location] => .co.uk
        [x] => 1293148800
        [y] => 1
        [fullurl] => http://www.tttt.com/
    )

[16] => Array
    (
        [query] => tttt
        [location] => .com
        [x] => 1293148800
        [y] => 1
        [fullurl] => http://www.tttt.com/
    )

[14] => Array
    (
        [query] => tttt
        [location] => .com
        [x] => 1293235200
        [y] => 1
        [fullurl] => http://www.tttt.com/
    )

Answer 1

你可以这样做:

$byLocation = array();
foreach ($arr as $key => $item) {
    if (!isset($byLocation[$item['location']])) {
        $byLocation[$item['location']] = array();
    }
    $byLocation[$item['location']][$key] = $item;
}

然后例如$byLocation['.co.uk'][22]是原始数组的第一项.如果您不想保留原始密钥,只需省略它并使用[].