file:///home/ashu/Music/Collections/randomPicks/ipod%20on%20sep%2009/Coldplay-Sparks.mp3
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如何转换像上面的字符串,以获得我可以传递给的普通文件路径
file:///home/ashu/Music/Collections/randomPicks/ipod%20on%20sep%2009/Coldplay-Sparks.mp3
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Ala*_*avi 16
看看url2pathname:
import urllib2
path = urllib2.url2pathname("file:///home/ashu/Music/Collections/randomPicks/ipod%20on%20sep%2009/Coldplay-Sparks.mp3")
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Sen*_*ran 10
这被称为unquote.可以从urllib获得.
import urllib
urllib.unquote('%20')
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