如何将NSIndexpath转换为NSInteger或简单地转换为int？

Question

我需要将nsindexpath var转换为NsInteger或简单地转换为int.例如:

 int rowIndex = [mGoogleBaseTable selectedRow];
 //mGoogleBaseTable is a NSTable type in Macdevelopement..

&&

int rowIndex = [mGoogleBaseTable indexPathForSelectedRow];
//mGoogleBaseTable is a UITableView type in Iphone (iOS)Development.

selectedRow返回NSInteger,但indexPathForSelectedRow返回NSIndexPath ..

请帮助我如何实现这一目标.

Answer 1

如果

NSIndexPath *p = ... // some indexpath

然后

NSInteger row = p.row;
NSInteger section = p.section;

就这样!

Answer 2

也许,这可以帮到你

NSInteger variable = indexPath.row;

Answer 3

在Swift中:

    let section: Int = indexPath.section
    let row: Int = indexPath.row

Answer 4

我更喜欢这样做

NSNumber *selRow = [[NSNumber alloc] initWithInteger:indexPath.row];