Ruby将两个阵列合并为一个

Question

这是我的情况.我有2个阵列

@names = ["Tom", "Harry", "John"]

@emails = ["tom@gmail.com", "h@gmail.com", "j@gmail.com"]

我想将这两个组合成一些调用的Array/Hash,@list这样我就可以在我的视图中迭代这样的东西:

<% @list.each do |item| %>
<%= item.name %><br>
<%= item.email %><br>
<% end %>

我无法理解如何实现这一目标.有什么想法吗？

Answer 1

@names  = ["Tom", "Harry", "John"]
@emails = ["tom@gmail.com", "h@gmail.com", "j@gmail.com"]

@list = @names.zip( @emails )
#=> [["Tom", "tom@gmail.com"], ["Harry", "h@gmail.com"], ["John", "j@gmail.com"]]

@list.each do |name,email|
  # When a block is passed an array you can automatically "destructure"
  # the array parts into named variables. Yay for Ruby!
  p "#{name} <#{email}>"
end
#=> "Tom <tom@gmail.com>"
#=> "Harry <h@gmail.com>"
#=> "John <j@gmail.com>"

@urls = ["yahoo.com", "ebay.com", "google.com"]

# Zipping multiple arrays together
@names.zip( @emails, @urls ).each do |name,email,url|
  p "#{name} <#{email}> :: #{url}"
end
#=> "Tom <tom@gmail.com> :: yahoo.com"
#=> "Harry <h@gmail.com> :: ebay.com"
#=> "John <j@gmail.com> :: google.com"

Answer 2

只是为了与众不同:

[@names, @emails, @urls].transpose.each do |name, email, url|
  # . . .
end

这类似于Array#zip所做的,除了在这种情况下不会有任何短行的nil填充; 如果缺少某些东西,将引发异常.

Answer 3

Hash[*names.zip(emails).flatten]

这将为您提供名称=>电子邮件的哈希.