Tin*_*son 9 java inheritance json jax-rs
我尝试了一些我在搜索时发现的东西,但没有任何帮助,或者我没有正确实现它.
我得到的错误
Direct self-reference leading to cycle (through reference chain: io.test.entity.bone.Special["appInstance"]->io.test.entity.platform.ApplicationInstance["appInstance"])
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这两个都扩展了基本实体,并且在基础(超类)中也有它appInstance
.
基本实体看起来与此类似
@MappedSuperclass
public abstract class BaseEntity implements Comparable, Serializable {
@ManyToOne
protected ApplicationInstance appInstance;
//getter & setter
}
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应用程序实体如下所示
public class ApplicationInstance extends BaseEntity implements Serializable {
private List<User> users;
// some other properties (would all have the same base and application instance . User entity will look similar to the Special.)
}
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特殊实体
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY, property = "objectType")
@JsonIgnoreProperties({"createdBy", "appInstance", "lastUpdatedBy"})
public class Special extends BaseEntity implements Serializable {
@NotNull
@Column(nullable = false)
private String name;
@Column(length = Short.MAX_VALUE)
private String description;
@NotNull
@Column(nullable = false)
private Double price;
@OneToOne
private Attachment image;
@Enumerated(EnumType.STRING)
@ElementCollection(targetClass = SpecialTag.class)
@CollectionTable(name = "special_tags")
@Column(name = "specialtag")
private List<SpecialTag> specialTags;
@Temporal(TemporalType.TIME)
private Date specialStartTime;
@Temporal(TemporalType.TIME)
private Date specialEndTime;
@Enumerated(EnumType.STRING)
@ElementCollection(targetClass = WeekDay.class)
@CollectionTable(name = "available_week_days")
@Column(name = "weekday")
private List<WeekDay> availableWeekDays;
@OneToMany(mappedBy = "special", cascade = CascadeType.REFRESH)
private List<SpecialStatus> statuses;
@OneToMany(mappedBy = "special", cascade = CascadeType.REFRESH)
private List<SpecialReview> specialReviews;
@Transient
private Integer viewed;
private Boolean launched;
@OneToMany(mappedBy = "special")
private List<CampaignSpecial> specialCampaigns;
@Override
@JsonIgnore
public ApplicationInstance getAppInstance() {
return super.getAppInstance();
}
}
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Special中的所有实体都继承自BaseEntity,其中包含AppInstance
然后我有一个方法来获得特殊
@GET
@Path("{ref}")
@Produces(MediaType.APPLICATION_JSON)
@Consumes(value = MediaType.TEXT_PLAIN)
public Special findByGuestRef(@PathParam("ref") String pRefeference) {
// find the special and return it
return special;
}
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在特殊实体上我尝试了以下内容
上面的链接
这些解决方案都不起作用.难道我做错了什么?
注意:是否也可以编辑特殊,因为其他实体位于不同的包中,并且不想编辑它们.
通常,排除响应中的属性就像@JsonIgnore
向其 getter 添加注释一样简单,但如果您不想将此注释添加到父类,则可以覆盖 getter,然后在其上添加注释:
public class Special extends BaseEntity implements Serializable {
...
@JsonIgnore
public ApplicationInstance getAppInstance() {
return this.appInstance;
}
...
}
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注意:由于有多个框架,请确保您使用正确的@JsonIgnore
注释,否则它将被忽略,例如,请参阅此答案。
另一种选择,更“手动”,只是为响应创建一个 bean,它是特殊实例的子集:
@GET
@Path("{ref}")
@Produces(MediaType.APPLICATION_JSON)
@Consumes(value = MediaType.TEXT_PLAIN)
public SpecialDTO findByGuestRef(@PathParam("ref") String pRefeference) {
// find the special and return it
return new SpecialDTO(special);
}
public class SpecialDTO {
//declare here only the attributes that you want in your response
public SpecialDTO(Special sp) {
this.attr=sp.attr; // populate the needed attributes
}
}
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