vir*_*tor 5 python parsing pyparsing associativity
我试图弄清楚如何做一个左关联表达式,其中递归(不包含在任何东西)表达式是可能的.例如,我想做:
expr + OP + expr
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它分析2个操作,如1 x 2 x 3
入(expr OP expr) OP expr
结果.
如果我试图阻止expr
无限递归解析,我可以做类似的事情:
expr -> Group(simple_expr + OP + expr)
| simple_expr
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但后来我得到了expr OP (expr OR expr)
结果.
如何强制左侧绑定?
编辑:我知道operatorPrecedence
但是当操作员"IS" + Optional("NOT")
或类似时,它似乎没有正确匹配.
下面是一个示例解析操作,它将获取令牌的平面列表并将它们嵌套,就好像左递归解析一样:
from pyparsing import *
# parse action -maker
def makeLRlike(numterms):
if numterms is None:
# None operator can only by binary op
initlen = 2
incr = 1
else:
initlen = {0:1,1:2,2:3,3:5}[numterms]
incr = {0:1,1:1,2:2,3:4}[numterms]
# define parse action for this number of terms,
# to convert flat list of tokens into nested list
def pa(s,l,t):
t = t[0]
if len(t) > initlen:
ret = ParseResults(t[:initlen])
i = initlen
while i < len(t):
ret = ParseResults([ret] + t[i:i+incr])
i += incr
return ParseResults([ret])
return pa
# setup a simple grammar for 4-function arithmetic
varname = oneOf(list(alphas))
integer = Word(nums)
operand = integer | varname
# ordinary opPrec definition
arith1 = operatorPrecedence(operand,
[
(None, 2, opAssoc.LEFT),
(oneOf("* /"), 2, opAssoc.LEFT),
(oneOf("+ -"), 2, opAssoc.LEFT),
])
# opPrec definition with parseAction makeLRlike
arith2 = operatorPrecedence(operand,
[
(None, 2, opAssoc.LEFT, makeLRlike(None)),
(oneOf("* /"), 2, opAssoc.LEFT, makeLRlike(2)),
(oneOf("+ -"), 2, opAssoc.LEFT, makeLRlike(2)),
])
# parse a few test strings, using both parsers
for arith in (arith1, arith2):
print arith.parseString("A+B+C+D+E")[0]
print arith.parseString("A+B+C*D+E")[0]
print arith.parseString("12AX+34BY+C*5DZ+E")[0]
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打印:
(正常)
['A', '+', 'B', '+', 'C', '+', 'D', '+', 'E']
['A', '+', 'B', '+', ['C', '*', 'D'], '+', 'E']
[['12', 'A', 'X'], '+', ['34', 'B', 'Y'], '+', ['C', '*', ['5', 'D', 'Z']], '+', 'E']
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(LR-等)
[[[['A', '+', 'B'], '+', 'C'], '+', 'D'], '+', 'E']
[[['A', '+', 'B'], '+', ['C', '*', 'D']], '+', 'E']
[[[[['12', 'A'], 'X'], '+', [['34', 'B'], 'Y']], '+', ['C', '*', [['5', 'D'], 'Z']]], '+', 'E']
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