JAXB - 如何在没有标头的情况下编组 java 对象

Question

我正在尝试封送一个 java 对象，但我想删除 Jaxb 引入的标头。

目的：

@XmlRootElement
public class FormElement implements Serializable {
    private String id;
    private String name;
    private Integer order;
}

预期输出：

<element>
    <id>asd</id>
    <name>asd</name>
    <order>1</order>
</element>

我的输出：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<formElement>
  <id>asd</id>
  <name>asd</name>
  <order>1</order>
</formElement>

我的元帅方法：

public String marshal() {
        JAXBContext context;
        try {
            context = JAXBContext.newInstance(FormElement.class);
            Marshaller marshaller = context.createMarshaller();
            StringWriter stringWriter = new StringWriter();
            marshaller.marshal(this, stringWriter);
            return stringWriter.toString();
        } catch (JAXBException e) {
        }
        return null;
    }

我怎样才能删除它？

提前致谢。

Answer 1

我已经解决了它

marshaller.setProperty(Marshaller.JAXB_FRAGMENT, Boolean.TRUE);

并添加(name = "element")到@XmlRootElement注释中。

正确的方法：

public String marshal() {
    JAXBContext context;
    try {
        context = JAXBContext.newInstance(FormElement.class);
        Marshaller marshaller = context.createMarshaller();
        StringWriter stringWriter = new StringWriter();
        marshaller.setProperty(Marshaller.JAXB_FRAGMENT, Boolean.TRUE);
        marshaller.marshal(this, stringWriter);
        return stringWriter.toString();
    } catch (JAXBException e) {
        String mess = "Error marshalling FormElement " + e.getMessage()
                + (e.getCause() != null ? ". " + e.getCause() : " ");
        System.out.println(mess);
    }
    return null;
}

以及正确的注释：

@XmlRootElement(name = "element")