将URL和@*转换为链接

Question

我正在收到HTTParty和Hashie的最新推文.

tweet = Hashie::Mash.new HTTParty.get(http://twitter.com/statuses/user_timeline/ethnt.json).first
puts tweet.text

我希望能够将每个link(http://*.*)和usernames(@.)转换为链接.两者的正则表达式是什么,以及如何实现它？

Answer 1

def link_urls_and_users s

    #regexps
    url = /( |^)http:\/\/([^\s]*\.[^\s]*)( |$)/
    user = /@(\w+)/

    #replace @usernames with links to that user
    while s =~ user
        s.sub! "@#{$1}", "<a href='http://twitter.com/#{$1}' >#{$1}</a>"
    end

    #replace urls with links
    while s =~ url
        name = $2
        s.sub! /( |^)http:\/\/#{name}( |$)/, " <a href='http://#{name}' >#{name}</a> "
    end

     s

end


puts link_urls_and_users(tweet.text)

只要 URL 用空格填充或位于推文的开头和/或结尾，这种方法就有效。