Har*_*han 2 c string loops fgets
我有这样的文本文件
"input"
height : 227
width : 227
depth : 3
"conv"
num_output : 96
pad : 0
kernel_size : 11
stride : 4
group : 1
"relu"
"pool"
kernel_size : 3
stride : 2
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我在循环中读它(这是部分代码)
char line[100];
while ((fgets(line, sizeof(line), filePtr))) {
if (line[0] != "\n") {
sscanf(line, "%15s : %15s", tmpstr1, tmpstr2);
printf("%s\n", tmpstr2);
printf("line = %s", line);
} else
break;
}
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但我观察到if
条件总是成立,输出如下
"input"
227
line = height : 227
227
line = width : 227
3
line = depth : 3
3
line =
3
line = "conv"
96
line = num_output : 96
0
line = pad : 0
11
line = kernel_size : 11
4
line = stride : 4
1
line = group : 1
1
line =
1
line = "relu"
1
line =
1
line = "pool"
3
line = kernel_size : 3
2
line = stride : 2
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我也尝试过比较\0
但结果不会改变.请指出我哪里出错了.
PS:我正在使用Ubuntu 16.04 64位机器和gcc 5.2.1.
换行符是一个字符,而不是字符串,所以改变这个:
line[0] != "\n"
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对此:
line[0] != '\n'
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启用编译器警告(-Wall
GCC中的标志),您应该看到如下内容:
warning: comparison between pointer and integer
warning: comparison with string literal results in unspecified behavior [-Waddress]
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