'...'不是后缀一元运算符 - Swift 3

Question

我只想删除一部分字符串.

if let dotRange = detailArticleContent?.range(of: "<iframe") {

    detailArticleContent.removeSubrange( dotRange.lowerBound... < detailArticleContent.endIndex )
    //In this line i got err : '...' is not a postfix unary operator 

   }

Answer 1

就我而言，我在0..<和之间给出了空格dictionary.count之间给出了空格

正确的一项是：

0..<dictionary.count

//Wrong 
let dictionary = dic["predictions"] as! [String:Any]
    print(dictionary)
    for index in 0..< dictionary.count {
        print(<#T##items: Any...##Any#>)
    }

//Correct 
let dictionary = dic["predictions"] as! [String:Any]
    print(dictionary)
    for index in 0..<dictionary.count {
        print(<#T##items: Any...##Any#>)
    }

Answer 2

使用...(近距离)或..<(近距离,前一个),没有什么比这更好的了... <