Zend和Jquery(Ajax Post)

Question

我正在使用zend框架,我想使用Jquery ajax post获取POST数据,以便在不刷新页面的情况下进行保存.

//submit.js

$(function() {

    $('#buttonSaveDetails').click(function (){
        var details = $('textarea#details').val();
        var id = $('#task_id').val();
        $.ajax({
            type: 'POST',
            url: 'http://localhost/myproject/public/module/save',
            async: false,
            data: 'id=' + id + '&details=' + details,
            success: function(responseText) {
                //alert(responseText)
                console.log(responseText);
            }

        });
    });
});

在我的控制器上,我只是不知道如何从ajax中检索POST数据.

public function saveAction() 
{

    $data = $this->_request->getPost();
    echo $id = $data['id'];
    echo $details = $data['details'];
    //this wont work;
}

提前致谢.

Answer 1

将$.ajax's dataType选项设置为'json',并修改成功回调以从接收的JSON中读取:

$('#buttonSaveDetails').click(function (){
    var details = $('textarea#details').val();
    var id = $('#task_id').val();
    $.ajax({
            type: 'POST',
            dataType: 'json',
            url: 'http://localhost/myproject/public/module/save',
            async: false,

            // you can use an object here
            data: { id: id, details: details },
            success: function(json) {
                console.log(json.id + ' ' + json.details);
            }
    });

    // you might need to do this, to prevent anchors from following
    // or form controls from submitting
    return false;
});

从您的控制器,发送如下数据:

$data = $this->_request->getPost();
echo Zend_Json::encode(array('id' => $data['id'], 'details' => $data['details']));

作为结束点,请确保已禁用自动视图呈现,因此返回客户端的唯一输出是JSON对象.