如何使用php和codeigniter隐藏检索到的数据值的重复部分

Question

由于这个MySQL语句,我已经获得了下表

SELECT * FROM expenses, income 
WHERE expenses.projectname=income.projectname 
AND expenses.task=income.task

这些是我的项目表中的字段

这些是我的任务表的字段

在此表中,一个项目有许多任务.因此项目,客户,项目开始和结束日期列无意义地重复.如何才能为所有任务显示一次？如何在这里应用PHP隐藏逻辑？下图显示了我需要实现的目标.通过MySQL查询检索数据.但是我怎样才能隐藏重复的不必要的值 这是CodeIgniter视图页面

<table class="table table-lg">
<thead >
    <tr class="filters">

       <th><input type="text" class="form-control" placeholder="Project" disabled></th>
        <th><input type="text" class="form-control" placeholder="Employee" disabled></th>
        <th><input type="text" class="form-control" placeholder="Task" disabled></th>
        <th><input type="text" class="form-control" placeholder="Expense" disabled></th>
        <th><input type="text" class="form-control" placeholder="Amount" disabled></th>
        <th><input type="text" class="form-control" placeholder="Paid/Not" disabled></th>
        <th><input type="text" class="form-control" placeholder="Client" disabled></th>
        <th><input type="text" class="form-control" placeholder="Cost" disabled></th>
        <th><input type="text" class="form-control" placeholder="Income " disabled></th>
        <th><input type="text" class="form-control" placeholder="Date" disabled></th>

    </tr>
</thead>
<tbody>
<?php
if(isset($view_data1) && is_array($view_data1) && count($view_data1)): $i=1;
foreach ($view_data1 as $key => $data) { 
?>

<tr <?php if($i%2==0){echo 'class="even"';}else{echo'class="odd"';}?>>

    <td><?php echo $data['projectname']; ?></td> 
    <td><?php echo $data['employee']; ?></td> 
    <td><?php echo $data['task']; ?></td> 
    <td><?php echo $data['ExpenseName']; ?></td> 
    <td><?php echo $data['ExpenseAmount']; ?></td>
    <td><?php echo $data['pn']; ?></td>  
   <td><?php echo $data['cname']; ?></td>
   <td><?php echo $data['taskcost']; ?></td> 
   <td><?php echo $data['amount']; ?></td> 
   <td><?php echo $data['datetimepicker_mask']; ?></td> 
</tr>
<?php
    $i++;
      }
    else:
?>
<tr>
    <td colspan="7" align="center" >No Records Found..</td>
</tr>
<?php
    endif;
?>
</tbody>                
</table>

Answer 1

不要同时选择两个表。加入他们的条件。

SELECT expenses.*,income.*,expenses.id as p_id FROM expenses
join income ON expenses.task=income.task AND expenses.projectname=income.projectname

更改每个部分的视图

<table class="table table-lg">
<thead >
    <tr class="filters">

       <th ><input type="text" class="form-control" placeholder="Project" disabled></th>
        <th ><input type="text" class="form-control" placeholder="Employee" disabled></th>
        <th ><input type="text" class="form-control" placeholder="Task" disabled></th>
        <th ><input type="text" class="form-control" placeholder="Expense" disabled></th>
        <th ><input type="text" class="form-control" placeholder="Amount" disabled></th>
        <th ><input type="text" class="form-control" placeholder="Paid/Not" disabled></th>
        <th ><input type="text" class="form-control" placeholder="Client" disabled></th>
        <th ><input type="text" class="form-control" placeholder="Cost" disabled></th>
        <th ><input type="text" class="form-control" placeholder="Income " disabled></th>
        <th ><input type="text" class="form-control" placeholder="Date" disabled></th>
    </tr>
</thead>
<tbody>
<?php
if(isset($view_data1) && is_array($view_data1) && count($view_data1)): $i=1;
$is_exists=array();
foreach ($view_data1 as $key => $data) { 
?>

<tr <?php if($i%2==0){echo 'class="even"';}else{echo'class="odd"';}?>>
<?php
    if(!in_array($data['p_id'], $is_exists)){
        $is_exists[]=$data['p_id'];
    ?>
        <td><?php echo $data['projectname']; ?></td> 
        <td><?php echo $data['employee']; ?></td> 
        <td><?php echo $data['task']; ?></td> 
        <td><?php echo $data['ExpenseName']; ?></td> 
    <?php
    }else{
     echo "<td rowspan='4'></td>";
    }
    ?>

   <td><?php echo $data['ExpenseAmount']; ?></td>
   <td><?php echo $data['pn']; ?></td>  
   <td><?php echo $data['cname']; ?></td>
   <td><?php echo $data['taskcost']; ?></td> 
   <td><?php echo $data['amount']; ?></td> 
   <td><?php echo $data['datetimepicker_mask']; ?></td> 
</tr>
<?php
    $i++;
      }
    else:
?>
<tr>
    <td colspan="7" align="center" >No Records Found..</td>
</tr>
<?php
    endif;
?>

</tbody>                
</table>