UMA*_*MAR 14 serialization android
朋友们,
我正在使用以下代码将Serializable对象写入外部存储.
它抛出我的错误java.io.NotSerializableException甚至我的对象是可序列化的任何人指导我我在做什么错?
public class MyClass implements Serializable
{
// other veriable stuff here...
public String title;
public String startTime;
public String endTime;
public boolean classEnabled;
public Context myContext;
public MyClass(Context context,String title, String startTime, boolean enable){
this.title = title;
this.startTime = startTime;
this.classEnabled = enable;
this.myContext = context;
}
public boolean saveObject(MyClass obj) {
final File suspend_f=new File(cacheDir, "test");
FileOutputStream fos = null;
ObjectOutputStream oos = null;
boolean keep = true;
try {
fos = new FileOutputStream(suspend_f);
oos = new ObjectOutputStream(fos);
oos.writeObject(obj); // exception throws here
}
catch (Exception e) {
keep = false;
}
finally {
try {
if (oos != null) oos.close();
if (fos != null) fos.close();
if (keep == false) suspend_f.delete();
}
catch (Exception e) { /* do nothing */ }
}
return keep;
}
}
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并从活动类调用以保存它
MyClass m= new MyClass(this, "hello", "abc", true);
boolean result =m.saveObject(m);
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任何帮助,将不胜感激.
Jes*_*eke 54
由于您的类中的Context字段,这会失败.上下文对象不可序列化.
根据Serializable文档 - "当遍历图形时,可能会遇到不支持Serializable接口的对象.在这种情况下,将抛出NotSerializableException并识别非可序列化对象的类."
您可以完全删除Context字段,也可以将transient属性应用于Context字段,以便不对其进行序列化.
public class MyClass implements Serializable
{
...
public transient Context myContext;
...
}
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