字符串中的街道地址搜索 - Python 或 Ruby

Question

嘿，我想知道如何在 Python/Ruby 中的字符串中找到街道地址？

也许通过正则表达式？

另外，它将采用以下格式（美国）

420 Fanboy Lane, 库比蒂诺 CA

谢谢！

Answer 1

也许您想看看pypostal。pypostal 是 libpostal 的官方 Python 绑定。

根据 Mike Bethany 的例子，我做了这个小例子：

from postal.parser import parse_address

addresses = [
    "420 Fanboy Lane, Cupertino CA 12345",
    "1829 William Tell Oveture, by Gioachino Rossini 88421",
    "114801 Western East Avenue Apt. B32, Funky Township CA 12345",
    "1 Infinite Loop, Cupertino CA 12345-1234",
    "420 time!",
]

for address in addresses:
    print parse_address(address)
    print "*" * 60

>     [(u'420', u'house_number'), (u'fanboy lane', u'road'), (u'cupertino', u'city'), (u'ca', u'state'), (u'12345', u'postcode')]
>     ************************************************************
>     [(u'1829', u'house_number'), (u'william tell', u'road'), (u'oveture by gioachino', u'house'), (u'rossini', u'road'), (u'88421',
> u'postcode')]
>     ************************************************************
>     [(u'114801', u'house_number'), (u'western east avenue apt.', u'road'), (u'b32', u'postcode'), (u'funky', u'road'), (u'township',
> u'city'), (u'ca', u'state'), (u'12345', u'postcode')]
>     ************************************************************
>     [(u'1', u'house_number'), (u'infinite loop', u'road'), (u'cupertino', u'city'), (u'ca', u'state'), (u'12345-1234',
> u'postcode')]
>     ************************************************************
>     [(u'420', u'house_number'), (u'time !', u'house')]
>     ************************************************************