我有以下数据框:
df <- structure(list(BoneMarrow = c(30, 0, 0, 31138, 2703), Pulmonary = c(3380,
21223.3333333333, 0, 0, 27)), row.names = c("ATP1B1", "CYCS",
"DDX5", "GNB2L1", "PRR11"), class = "data.frame", .Names = c("BoneMarrow",
"Pulmonary"))
df
#> BoneMarrow Pulmonary
#> ATP1B1 30 3380.00
#> CYCS 0 21223.33
#> DDX5 0 0.00
#> GNB2L1 31138 0.00
#> PRR11 2703 27.00
Run Code Online (Sandbox Code Playgroud)
我想要做的是摆脱任何列中值<8的行.我尝试了这个,但行名称(例如ATP1B1,CYCS等)消失了:
> df %>% filter(!apply(., 1, function(row) any(row <= 8 )))
BoneMarrow Pulmonary
1 30 3380
2 2703 27
Run Code Online (Sandbox Code Playgroud)
我怎样才能在dplyr链中保留它?
mt1*_*022 44
您可以将rownames转换为列并在过滤后恢复:
library(dplyr)
library(tibble) # for `rownames_to_column` and `column_to_rownames`
df %>%
rownames_to_column('gene') %>%
filter_if(is.numeric, all_vars(. >= 8)) %>%
column_to_rownames('gene')
# BoneMarrow Pulmonary
# ATP1B1 30 3380
# PRR11 2703 27
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
15582 次 |
| 最近记录: |