我在下面有一个类,想要删除包含相同名称的重复者,如何使用Java8 Lambda,预期List包含p1,p3,如下所示.
public class Person {
public int id;
public String name;
public String city;
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getCity() {
return city;
}
public void setCity(String city) {
this.city = city;
}
}
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import java.util.ArrayList;
import java.util.List;
public class Testing {
public static void main(String[] args) {
List<Person> persons = new ArrayList<>();
Person p1 = new Person();
p1.setId(1);
p1.setName("Venkat");
p1.setCity("Bangalore");
Person p2 = new Person();
p2.setId(2);
p2.setName("Venkat");
p2.setCity("Bangalore");
Person p3 = new Person();
p3.setId(3);
p3.setName("Kumar");
p3.setCity("Chennai");
persons.add(p1);
persons.add(p2);
persons.add(p3);
}
}
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Eug*_*ene 14
您可以过滤掉它们并生成一个唯一的Set
:
Set<Person> set = persons.stream()
.collect(Collectors.toCollection(() ->
new TreeSet<>(Comparator.comparing(Person::getName))));
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甚至更好:
Set<String> namesAlreadySeen = new HashSet<>();
persons.removeIf(p -> !namesAlreadySeen.add(p.getName()));
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Tar*_*nyk 11
List<Person> personsWithoutDuplicates = persons.stream()
.distinct()
.collect(Collectors.toList());
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