使用索引号jquery检索值

Wil*_*son 3 html css jquery

我有这个下面的代码所有三个DIV有相同的类名我想要做的是通过使用jquery索引号访问/检索第二个DIV值第二个DIV的值是3.21,我试图使用此代码检索div.OddVal.index(2)没有运气任何想法的人我错了吗?

<div class="ThreeWayCol OddsCol1">
   <div class="OddVal ng-pristine ng-untouched ng-valid ng-binding ng-scope ng-not-empty" ng-repeat="sel in event._matchMarket.selections" ng-model="sel" ng-class="{'Sel': oddSelections[event.id].sels[sel.id]}" ng-click="selectOdd(event,event._matchMarket,sel)">3.37</div>
   <div class="OddVal ng-pristine ng-untouched ng-valid ng-binding ng-scope ng-not-empty" ng-repeat="sel in event._matchMarket.selections" ng-model="sel" ng-class="{'Sel': oddSelections[event.id].sels[sel.id]}" ng-click="selectOdd(event,event._matchMarket,sel)">3.21</div>
   <div class="OddVal ng-pristine ng-untouched ng-valid ng-binding ng-scope ng-not-empty" ng-repeat="sel in event._matchMarket.selections" ng-model="sel" ng-class="{'Sel': oddSelections[event.id].sels[sel.id]}" ng-click="selectOdd(event,event._matchMarket,sel)">2.07</div>
</div>
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Ori*_*ori 5

你用jQuery标记了这个问题,所以我相信你正在寻找.eq():

将匹配元素集减少到指定索引处的元素集.

console.log($('.OddVal').eq(1).text());
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<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="OddVal ng-pristine ng-untouched ng-valid ng-binding ng-scope ng-not-empty" ng-repeat="sel in event._matchMarket.selections" ng-model="sel" ng-class="{'Sel': oddSelections[event.id].sels[sel.id]}" ng-click="selectOdd(event,event._matchMarket,sel)">3.37</div>

<div class="OddVal ng-pristine ng-untouched ng-valid ng-binding ng-scope ng-not-empty" ng-repeat="sel in event._matchMarket.selections" ng-model="sel" ng-class="{'Sel': oddSelections[event.id].sels[sel.id]}" ng-click="selectOdd(event,event._matchMarket,sel)">3.21</div>

<div class="OddVal ng-pristine ng-untouched ng-valid ng-binding ng-scope ng-not-empty" ng-repeat="sel in event._matchMarket.selections" ng-model="sel" ng-class="{'Sel': oddSelections[event.id].sels[sel.id]}" ng-click="selectOdd(event,event._matchMarket,sel)">2.07</div>
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