如何在StackNavigator中将参数传递给屏幕？

Question

我的React Native代码:

import React, { Component } from 'react';
import { AppRegistry, ActivityIndicator, StyleSheet, ListView, 
  Text, Button, TouchableHighlight, View } from 'react-native';

import { StackNavigator } from 'react-navigation';
import DetailsPage from './src/screens/DetailsPage';

class HomeScreen extends React.Component {

   constructor() {
    super();
    const ds = new ListView.DataSource({rowHasChanged: (r1, r2) => r1 !== r2});
    this.state = {
      userDataSource: ds,
    };
  }

  componentDidMount(){
      this.fetchUsers();
  }

    fetchUsers(){

        fetch('https://jsonplaceholder.typicode.com/users')
            .then((response) => response.json())
            .then((response) => {
                this.setState({
                    userDataSource: this.state.userDataSource.cloneWithRows(response)
                });
            });
    }

    onPress(user){
        this.props.navigator.push({
            id: 'DetailPage'
        });
    }

  renderRow(user, sectionID, rowID, highlightRow){
      return(
      <TouchableHighlight onPress={()=>{this.onPress(user)} } >
      <View style={styles.row}>
        <Text style={styles.rowText}> {user.name} </Text>

      </View>
      </TouchableHighlight>
      )
  }


  render(){
      return(
          <ListView
            dataSource = {this.state.userDataSource}
            renderRow = {this.renderRow.bind(this)}
          />
      )
  } 
}

导航配置:

const NavigationTest = StackNavigator({
  Home: { screen: HomeScreen },
  DetailsPage: { screen: DetailsPage },
});

详细信息屏幕是:

import React, { Component } from 'react';
import { StyleSheet, Text, View } from 'react-native';

import styles from '../styles';


export default class DetailsPage extends React.Component {
  static navigationOptions = ({ navigation }) => ({
    title: `User: ${navigation.state.params.user.name}`,
  });
  render() {
    const { params } = this.props.navigation.state;
    return (
      <View>
        <Text style={styles.myStyle}>Name: {params.name}</Text>
        <Text style={styles.myStyle}>Email: {params.email}</Text>
      </View>
    );
  }
}

我无法通过代码传递user给DetailsPage:

onPress(user){
        this.props.navigator.push({
            id: 'DetailPage'
        });
    }

我想导航到DetailPage与onPress功能.如果我提醒它:

onPress(user){ Alert.alert(user.name)}

我确实得到了价值,但我如何将其传递给其他页面？

非常感谢!

Answer 1

你可以使用navigate函数的第二个参数传递params :

onPress(user) {
  this.props.navigation.navigate(
    'DetailPage',
    { user },
  );
}

然后访问它们this.props.navigation.state.params.例如在你的DetailsPage:

<Text style={styles.myStyle}>{this.props.navigation.state.params.user.name}</Text>

参考:https://reactnavigation.org/docs/params.html

Answer 2

在反应钩子中，参数使用 useNavigation 发送导航

import { useNavigation } from '@react-navigation/native';

const navigation = useNavigation();

<Button
      title="Back"
      onPress={() => {
        navigation.navigate('MyScreen',{name:'test'});
      }}
    />

然后使用 useNavigationParam 访问它们

function MyScreen() {
  const name = useNavigationParam('name');
  return <p>name is {name}</p>;
}

Answer 3

看到这个。

它解决了我的问题。

this.props.navigation.navigate("**stack_Name**", {
 screen:"screen_name_connect_with_**stack_name**",
 params:{
 user:"anything_string_or_object"
}
})