这就是我为我的摇滚剪刀游戏提出的:
import random
from time import sleep
print "Please select: "
print "1 Rock"
print "2 Paper"
print "3 Scissors"
player = input ("Choose from 1-3: ")
if player == 1:
print "You choose Rock"
sleep (2)
print "CPU chooses Paper"
sleep (.5)
print "You lose, and you will never win!"
elif player == 2:
print "You choose Paper"
sleep (2)
print "CPU chooses Scissors"
sleep (.5)
print "You lose, and you will never win!"
else:
print "You choose Scissors"
sleep (2)
print "CPU chooses Rock"
sleep (.5)
print "You lose, and you will never win!"
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而我想要的程序是随机选择三个选项中的一个(石头剪刀),无论用户输入什么.我怎么能做到这一点?
syk*_*ora 29
好吧,你已经导入了随机模块,这是一个开始.
尝试random.choice函数.
>>> from random import choice
>>> cpu_choice = choice(('rock', 'paper', 'scissors'))
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import random
ROCK, PAPER, SCISSORS = 1, 2, 3
names = 'ROCK', 'PAPER', 'SCISSORS'
def beats(a, b):
if (a,b) in ((ROCK, PAPER), (PAPER, SCISSORS), (SCISSORS, ROCK)):
return False
return True
print "Please select: "
print "1 Rock"
print "2 Paper"
print "3 Scissors"
player = int(input ("Choose from 1-3: "))
cpu = random.choice((ROCK, PAPER, SCISSORS))
if cpu != player:
if beats(player, cpu):
print "player won"
else:
print "cpu won"
else:
print "tie!"
print names[player-1], "vs", names[cpu-1]
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