我有一个带有表单和一个按钮的登录页面来进行登录.当用户单击按钮时,我想评估密码和电子邮件,如果一切正确,则必须将用户重定向到另一个页面.
我的问题是我在登录html里面(<router-outlet></router-outlet>),这个新页面的所有信息都显示在登录页面的同一个地方,我不想混合这两个信息.我希望将登录信息与新信息分开.
我尝试使用window.location.href,但不能继续显示在登录的同一位置的信息.
这是我的路线配置.
export const routes: Routes = [
{ path: 'show_alunos', component: ListAlunosComponent }
];
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组件ListAlunosComponent是我想在验证用户凭据后显示的新页面.
app.component.html
<form class="form-signin">
<h2 class="form-signin-heading">Please sign in</h2>
<label for="inputEmail" class="sr-only">Email address</label>
<input [(ngModel)]="email" name="email" type="email" id="inputEmail" class="form-control" placeholder="Email address" required autofocus>
<label for="inputPassword" class="sr-only">Password</label>
<input [(ngModel)]="password" name="password" type="password" id="inputPassword" class="form-control" placeholder="Password" required>
<div class="checkbox">
<label>
<input type="checkbox" value="remember-me"> Remember me
</label>
</div>
<button class="btn btn-lg btn-primary btn-block" (click)="submit()" type="submit">Sign in</button>
</form>
<router-outlet></router-outlet>
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app.component.ts
mport { Component } from '@angular/core';
import { Router } from '@angular/router'
@Component({
selector: 'app-root',
templateUrl: './app.component.html',
styleUrls: ['./app.component.css']
})
export class AppComponent {
title = 'app';
public email: string;
public password: string;
constructor(private router: Router) {
this.email = "";
this.password = "";
}
public submit(): void {
this.router.navigateByUrl(['show_alunos']);
}
}
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app.router.ts
import { ModuleWithProviders } from '@angular/core';
import { Routes, RouterModule } from '@angular/router';
import { AppComponent } from './app.component';
import { ListAlunosComponent } from '../pages/list-alunos/list-
alunos.component';
// Route Configuration.
export const routes: Routes = [
{ path: 'show_alunos', component: ListAlunosComponent }
];
export const routing: ModuleWithProviders = RouterModule.forRoot(routes);
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Fie*_*Dev 19
检查完电子邮件和发送邮件后,请尝试:
router.navigate(['/show_alunos'])
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并在构造函数声明
constructor (private router: Router)
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并从"@ angular/router"导入{Router};
更新:
简单示例如何使用Ruter:
your.component.html:
<form [formGroup]="myForm" (ngSubmit)="onSubmit()">
<input type="text" formControlName="Email">
<input type="password" formContolName="Password">
<input type="submit" value="login">
</form>
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your.component.ts:
import { Component, OnInit } from '@angular/core';
import { FormControl, FormGroup } from "@angular/forms";
import { Router } from "@angular/router";
@Component({
selector: 'component-tag-name',
templateUrl: './your.component.html'
})
export class YourComponentName implements OnInit {
myForm: FormGroup;
constructor(private router: Router) {}
ngOnInit(){
this.myForm = this.FormGroup({
'Email': new FormConrol(null, [Validators.required]),
'Password': new FormControl(null, [Validators.required])
})
}
onSubmit(){
let email = this.myForm.get('Email').value;
let password = this.myForm.get('Password').value;
if (email === 'your value' && password === 'your value'){
this.router.navigate(['/show_alunos']);
}
}
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在yout app.module.ts中,您还需要导入此组件和ListAlunosComponent.然后你需要导入这个组件并写入你的路由配置.ts文件:
{ path: 'show_alunos', component: ListAlunosComponent }
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