Sag*_*yal 5 android firebase firebase-realtime-database
在这里,我想根据id ="sd"检索Location子项的最后一项的纬度和经度.
这是代码:
Query query = mDatabase.child("Users").orderByChild("Id").equalTo(busId);
// busId = "sd"
query.addListenerForSingleValueEvent(new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot dataSnapshot) {
for(DataSnapshot user : dataSnapshot.getChildren()) {
Query lastItem = user.getRef().child("Location").orderByKey().limitToLast(1);
lastItem.addListenerForSingleValueEvent(new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot dataSnapshot) {
String lat = dataSnapshot.child("Latitude").getValue().toString();
}
@Override
public void onCancelled(DatabaseError databaseError) {
}
});
break;
}
}
Run Code Online (Sandbox Code Playgroud)
我怎样才能做到这一点?谢谢
Android 版请使用此代码:
DatabaseReference rootRef = FirebaseDatabase.getInstance().getReference();
DatabaseReference userRef = rootRef.child("Users");
ValueEventListener eventListener = new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot dataSnapshot) {
for(DataSnapshot ds : dataSnapshot.getChildren()) {
String Id = ds.child("Id").getValue(String.class);
if(Id.equals("sd")) {
Query q = ds.child("Location").getRef().orderByKey().limitToLast(1);
ValueEventListener valueEventListener = new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot dataSnapshot) {
for(DataSnapshot child : dataSnapshot.getChildren()) {
Double latitude = child.child("Latitude").getValue(Double.class);
Double longitude = child.child("Longitude").getValue(Double.class);
Log.d("TAG", latitude + " / " + longitude);
}
}
@Override
public void onCancelled(DatabaseError databaseError) {}
};
q.addListenerForSingleValueEvent(valueEventListener);
}
}
}
@Override
public void onCancelled(DatabaseError databaseError) {}
};
userRef.addListenerForSingleValueEvent(eventListener);
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
998 次 |
| 最近记录: |