我使用mercurial来控制目录中的几个文件.假设我有10个提交(10个更改集或修订版).我想查看一个特定的文件,比如thisFile.py,看看它的第7版.我不想恢复到这个旧版本.我不想在以前的版本中进行任何更改或修复任何错误.我只是想看到它,而不会以任何方式影响文件的最新版本或mercurial历史.有一个简单的方法吗?
Joe*_*sky 66
将hg cat
命令与-r
(revision)参数一起使用.
hg cat path_to/myfile.cpp -r 46
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其中46是修订号(用于hg log
查看修订历史)
Thi*_*ilo 10
hg cat [OPTION]... FILE...
Print the specified files as they were at the given revision.
If no revision is given, the parent of the working directory is used,
or tip if no revision is checked out.
Output may be to a file, in which case the name of the file is given
using a format string. The formatting rules are the same as for the
export command, with the following additions:
%s: basename of file being printed
%d: dirname of file being printed, or '.' if in repository root
%p: root-relative path name of file being printed
Returns 0 on success.
options:
-o, --output print output to file with formatted name
-r, --rev print the given revision
--decode apply any matching decode filter
-I, --include include names matching the given patterns
-X, --exclude exclude names matching the given patterns
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要提取特定文件的特定版本,可以在Windows中执行此操作:
hg cat "<FileToBeExtractedPath>" -r 9 > "<ExtractionPath>"
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这里,9是修订号.
甚至更好:
hg cat "<FileToBeExtractedPath>" -r 9 -o "<ExtractionPath>"
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