我有几乎可以工作的代码,但OnRequest方法充满了错误,我看到它是我认为的编译代码。将这段代码变成人类可读的代码有什么帮助吗?
[AsyncStateMachine(typeof(Service1.<OnRequest>d__24))]
public Task OnRequest(object sender, SessionEventArgs e)
{
Service1.<OnRequest>d__24 <OnRequest>d__;
<OnRequest>d__.<>4__this = this;
<OnRequest>d__.e = e;
<OnRequest>d__.<>t__builder = AsyncTaskMethodBuilder.Create();
<OnRequest>d__.<>1__state = -1;
AsyncTaskMethodBuilder <>t__builder = <OnRequest>d__.<>t__builder;
<>t__builder.Start<Service1.<OnRequest>d__24>(ref <OnRequest>d__);
return <OnRequest>d__.<>t__builder.Task;
}
Run Code Online (Sandbox Code Playgroud)
或者我在这里很无助,我不知道那是什么,如果我无法解决这个问题,我希望在最坏的情况下得到解释。
字符<和>无效C#的类型和变量名,但他们在完全有效的CIL代码。
ILSpy不会“规范化”名称,因此您会获得不可编译的代码,但您可以删除特殊字符来修复它:
[AsyncStateMachine(typeof(Service1.OnRequestd__24))]
public Task OnRequest(object sender, SessionEventArgs e)
{
Service1.OnRequestd__24 OnRequestd__;
OnRequestd__.__this = this;
OnRequestd__.e = e;
OnRequestd__.t__builder = AsyncTaskMethodBuilder.Create();
OnRequestd__.__state = -1;
AsyncTaskMethodBuilder t__builder = OnRequestd__.t__builder;
t__builder.Start<Service1.OnRequestd__24>(ref OnRequestd__);
return OnRequestd__.t__builder.Task;
}
Run Code Online (Sandbox Code Playgroud)
如果您还实现了引用类型,这将完美编译:
public class Service1
{
public struct OnRequestd__24 : IAsyncStateMachine
{
public ObjectPoolAutoTest __this;
public SessionEventArgs e;
public AsyncTaskMethodBuilder t__builder;
public int __state;
public void MoveNext() => throw new NotImplementedException();
public void SetStateMachine(IAsyncStateMachine stateMachine) => throw new NotImplementedException();
}
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
2820 次 |
| 最近记录: |