Jan*_*tze 1 exception-handling typescript angular2-observables angular
我想在我的全局异常处理程序中捕获HTTP错误.
异常处理程序适用于大多数异常,但不会捕获可观察的异常.我想要捕获的异常是HTTP异常.
这就是我尝试将HTTP可观察错误发送到异常处理程序的方法.
import { Injectable } from '@angular/core';
import { Request, XHRBackend, RequestOptions, Http, Response, RequestOptionsArgs } from '@angular/http';
import 'rxjs/add/operator/catch';
import 'rxjs/add/observable/throw';
import { HttpException } from '../exceptions/http-exception';
import {Observable} from 'rxjs/Observable';
@Injectable()
export class HttpErrorService extends Http {
constructor(backend: XHRBackend, defaultOptions: RequestOptions) {
super(backend, defaultOptions);
}
request(url: string | Request, options?: RequestOptionsArgs) {
return super.request(url, options).catch((error: Response) => {
// Bypass lint.
fail();
function fail() {
// Here I want to throw the exception to send it to the exception handler, but it should also execute return Observable.throw(error); So I can catch the exception at the subscribe.
throw new HttpException(error);
}
return Observable.throw(error);
});
}
}
Run Code Online (Sandbox Code Playgroud)
当然,这不起作用,因为抛出后的代码没有执行.
但抛出的异常也没有被捕获,可能是因为这是在一个可观察的情况下完成的.
有没有办法在全局异常处理程序中捕获异常,并且请求仍然可用于subscribe((res) => {}, (errRes) => {/*here*/})?
您需要返回从头开始创建的新observable:
@Injectable()
export class HttpErrorService extends Http {
constructor(backend: XHRBackend, defaultOptions: RequestOptions) {
super(backend, defaultOptions);
}
request(url: string | Request, options?: RequestOptionsArgs) {
return Observable.create(observer => {
super.request(url, options).subscribe(
res => observer.next(res), //simply passing success response
err => { //error handling
console.log("global error handler");
observer.error(err); //passing error to the method which invoked request
},
() => observer.complete() //passing onComplete event to the method which invoked request
);
});
}
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
6766 次 |
| 最近记录: |