hum*_*zed 3 android kotlin android-room
我正在尝试使用新的房间库,但我收到了这个错误
错误:查询有问题:[SQLITE_ERROR] SQL错误或缺少数据库(没有这样的表:Station)
错误:不确定如何将Cursor转换为此方法的返回类型
警告:未向注释处理器提供架构导出目录,因此我们无法导出架构.您可以提供
room.schemaLocation注释处理器参数或将exportSchema设置为false.错误:org.gradle.api.internal.tasks.compile.CompilationFailedException:编译失败; 请参阅编译器错误输出以获取详细信
RoomDatabase.kt
@Database(entities = TrolleyType::class), version = 2)
abstract class AppDatabase : RoomDatabase() {
abstract fun stationDao(): StationDao
}
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MyDao.kt
@Dao
interface MyDao {
@get:Query("SELECT * FROM Station")
val stations: List<Station>
@get:Query("SELECT * FROM TrolleyType")
val trolleyTypes: List<TrolleyType>
}
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的entites
@Entity
data class Station(
@PrimaryKey @ColumnInfo(name = "_id") var id: Int = 0,
@ColumnInfo(name = "StationName") var stationName: String? = "",
@ColumnInfo(name = "StationArabic") var stationArabic: String? = ""
)
@Entity
data class TrolleyType(
@PrimaryKey @ColumnInfo(name = "_id") var id: Int = 0,
@ColumnInfo(name = "Type") var stationName: String? = "",
@ColumnInfo(name = "TypeArabic") var stationArabic: String? = ""
)
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hum*_*zed 19
事实证明,我忘了将Station实体添加到RoomDatabase
添加后,每件事都按预期工作
@Database(entities = TrolleyType::class, Station::class), version = 2)
abstract class AppDatabase : RoomDatabase() {
abstract fun stationDao(): StationDao
}
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