这就是我用来根据枚举类型选择函数的方法。有没有我没有切换CalcMe功能的方法?
namespace ClassLibrary1
{
public class Playbox
{
//types:
//0 - red hair
//1 - blue hair
//defines function to input based on hairtype.
//red:
// input*10
//blue:
// input*12
public enum Phenotypes
{
red,
blue
}
static public int Red(int input)
{
return input*10;
}
static public int Blue(int input)
{
return input*12;
}
static public int CalcMe(Phenotypes phenotype, int input)
{
switch (phenotype)
{
case Phenotypes.red:
return Red(input);
case Phenotypes.blue:
return Blue(input);
default:
return 0;
}
}
public class MyObject
{
int something;
Phenotypes hairtype;
public MyObject()
{
Random randy = new Random();
this.hairtype = (Phenotypes)randy.Next(2); //random phenotype
this.something = CalcMe(hairtype, randy.Next(15)); //random something
}
}
}
}
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你可以使用这样的字典
Dictionary<Phenotypes, Func<int, int>> Mappings = new Dictionary<Phenotypes, Func<int, int>>()
{
{Phenotypes.red, x=> Red(x) },
{Phenotypes.blue, x=> Blue(x) }
};
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现在你可以这样称呼它
var something = Mappings[Phenotypes.blue](666);
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