jquery Tablesorter - 按<input value ="value">排序字段

Question

我想通过INPUT attr VALUE上的信息对第4和第5场进行排序

这是我的HTML:

<table class=tablesorter width="764" border=1 cellpadding=0 cellspacing=0 id="objective3">
    <thead>
    <tr>
      <th bgcolor="#396FAE" class="divtopheader1">Strategy</th>
      <th bgcolor="#396FAE" class="divtopheader1">Objective</th>
      <th bgcolor="#396FAE" class="divtopheader1">Status</th>
      <th bgcolor="#396FAE" class="divtopheader1">Target Date</th>
      <th bgcolor="#396FAE" class="divtopheader1">Target</th>
      <th bgcolor="#396FAE" class="divtopheader1">Actual</th>
      <th bgcolor="#396FAE" class="divtopheader1">Cumulative</th>
    </tr>
    </thead>
    <tbody>
    <tr>
      <td align="left" valign="top" class="tvertheadersm">Conservation</td>
      <td width="27%" class="tvertheadersm">statutory authority.</td>
      <td width="8%" align="center" valign="middle" class="tbody2">
          <input type=hidden value="1">
           <thewordIMGshouldgohere src="images/1" alt="Objective met" width=30 height=40 />
      </td>
      <td width="11%" align=center class="tbody2">
          <input type=hidden value="092010">September<br>2010</td>
          <td align=center class="tbody2">14 agencies</td>
      <td align=center class="tbody2">14 agencies</td>
      <td align=center class="tbody2">0 agencies</td>
    </tr>

这是我的jquery,在这里我只尝试第5场但是没有工作:

$(document).ready(function() {
    // add parser through the tablesorter addParser method
    $.tablesorter.addParser({
        // set a unique id
        id: 'input',
        is: function(s) {
            // return false so this parser is not auto detected
            return false;
        },
        format: function(s) {
            // format your data for normalization
            return $("td input",$(s)).attr("value");
        },
        // set type, either numeric or text
        type: 'numeric'
    });

    $("table").tablesorter({
        // pass the headers argument and assing a object
        headers: {
            // assign the secound column (we start counting zero)
            5: {
                sorter:'input'
            }
        }
    });
});

欢迎任何帮助!

节日快乐 :-)

内斯托尔

Answer 1

传递给format()函数的"s"是一个包含单元格内容的字符串.你应该重写你的功能看起来像这样

format: function(s) {
    // format your data for normalization
    return $($.trim(s)).val();
}

更新:仔细查看您的代码和tablesorter.addParser

看起来format()用3个参数调用,第3个是它应用的单元格.考虑到这一点,代码可以像这样重写:

format: function(s, table, cell) {
  return $('input', cell).val();
}

http://jsfiddle.net/RyCWM/1/