按JSON字段值排序

Question

我有一个像这样的json值的表:

-表格1

id    |   name   |   data
------+----------+---------------
1     | Test     | {"city_id": 3, "email":"test@test.com", "city_name":"something"}
2     | Test 2   | {"city_id": 1, "email":"test2@test2.com", "city_name":"another"}
3     | Test 3   | {"city_id": 6, "email":"test3@test3.com", "city_name":"blahblah"}

现在我想要SELECT记录order by data.city_name,所以我使用这段代码:

SELECT id, name, JSON_EXTRACT(data, 'city_name') AS cityName
FROM table1
ORDER BY cityName ASC

但是这个查询无法正确排序我的记录!

PS:city_name有UTF-8字符.

Answer 1

您似乎没有正确使用JSON_EXTRACT(),请尝试:

SELECT id, name, JSON_EXTRACT(data, '$.city_name') AS cityName 
FROM demo ORDER BY cityName ASC

演示小提琴

Answer 2

我通常将JSON 值 ( ->> ) 转换为正确的类型以便正确排序：

SELECT id, name, data->>'$.city_name' AS cityName
FROM table1
ORDER BY CAST(cityName AS CHAR) ASC

否则，您最终将排序为 blob（二进制），它们被视为二进制字符串（字节字符串），因此它们具有二进制字符集和排序规则，并且比较和排序基于列值中字节的数值（参考）。

Answer 3

我认为最简单的方法

SELECT * FROM YourTable order by data->"$.city_name" desc

Answer 4

检查这个。

SELECT Id ,name,SUBSTRING_INDEX(SUBSTRING_INDEX(data,'city_name":"',-1),'"',1) as CITY
FROM tempjson
order by SUBSTRING_INDEX(SUBSTRING_INDEX(data,'city_name":"',-1),'"',1)

输出 ：