我可以有一个与 Core Data 对象类型同名的结构吗?如果是这样,我如何在代码中区分两者?
编辑:例如,我有一个Track核心数据对象,当我从外部读取“跟踪”信息时,它是通过 json 传入的。我没有使用核心数据对象,因为它是一个托管对象,所以我使用了另一种结构。我也打算命名它Track,但是这可能会导致我不确定的冲突,所以目前我TrackStruct改为调用它。另外,这是正确的方法吗?
谢谢!
在经历了很多困难之后,我为您制作了一个示例项目。但我在这里发布主要概念。
您可以在此处获取示例项目。虽然我已经从本地
.plist文件加载了数据。您可以检查该loadPersonWithJSON(fromPath:)函数的工作。只需按照我的代码注释即可。
假设我有一个Person实体,Core-Data有两个String属性name和location。从 json 中我得到了类型为 的数组[[String:Any]]。现在我想将 json 数据映射到核心数据对象模型。
enum CoreDataError: String, Error {
case NoEntity = "ERROR: No Entity, Check the Entity Name"
}
enum JSONError: String, Error {
case NoData = "ERROR: no data"
case ConversionFailed = "ERROR: conversion from JSON failed"
}
typealias personJSONObjectType = [[String:String]]
class PersonTableViewController: UITableViewController {
var person: [Person] = []
override func viewWillAppear(_ animated: Bool) {
super.viewWillAppear(animated)
self.loadPersonWithJSON(fromPath: "your json URL in String format")
}
func loadPersonWithJSON(fromPath jsonURLString:String) {
guard let jsonURL = URL(string: jsonURLString) else {
print("Error creating an URL from \(jsonURLString)")
return
}
URLSession.shared.dataTask(with: jsonURL) { (data, response, error) in
do {
guard let data = data else {
throw JSONError.NoData
}
guard let json = try JSONSerialization.jsonObject(with: data, options: []) as? personJSONObjectType else {
throw JSONError.ConversionFailed
}
// Here you have your json data. Now map this data to your model object.
// First you need to have your shared App Delegate
guard let appDelegate = UIApplication.shared.delegate as? AppDelegate else {
print("No shared AppDelegate")
return
}
// Use shared App Delegate to have the persistent containers view context as managed object context. This will be used to verify whether your Entity exists or not
let managedObjectContext = appDelegate.persistentContainer.viewContext
// Get the Entity in your core data model
guard let entity = NSEntityDescription.entity(forEntityName: "Person", in: managedObjectContext) else {
throw CoreDataError.NoEntity
}
let persons = json.map({ (personInfo) -> Person in
let personName = personInfo["name"] as? String // use appropriate key for "name"
let personLocation = personInfo["location"] as? String // use appropriate key for "location"
// Get your object as Core data Managed object.
let aPerson = NSManagedObject(entity: entity, insertInto: managedObjectContext) as! Person
// Manipulate core data object with json data
aPerson.name = personName
aPerson.location = personLocation
// Manipulation done
return aPerson
})
self.person = persons
self.tableView.reloadData()
} catch let error as JSONError {
print(error.rawValue)
} catch let error as CoreDataError {
print(error.rawValue)
} catch let error as NSError {
print(error.debugDescription)
}
}.resume()
}
}
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您可以使用以下表视图数据源方法来检查是否有效:
// MARK: - Table view data source
override func numberOfSections(in tableView: UITableView) -> Int {
return 1
}
override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return self.person.count
}
override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: "Cell", for: indexPath)
let aPerson = self.person[indexPath.row]
cell.textLabel?.text = aPerson.name
cell.detailTextLabel?.text = aPerson.location
return cell
}
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