递归检索上一条记录的LAG()值

Hik*_*ari 6 sql-server recursion lag sql-server-2012

我进行了涉及LAG()的以下计算:

(lag(fValue,1,fValue) OVER (PARTITION BY Cluster ORDER BY iSequence) + fValue) / 2 as fValueAjusted

它取前一个(基于iSequence)记录的fValue,与当前记录之和,然后除以2。

但是,必须使用先前记录的fValueAjusted来执行此操作,而不是使用fValue。

这意味着第一条记录的fValueAjusted将是其自己的fValue。第二条记录的fValueAjusted将基于第一条记录的fValue。并且,从第三条记录开始,将基于前一条记录的fValueAjusted进行计算。

我需要对上一条记录的fValueAjusted进行递归计算的fValueAjusted。我不知道该怎么做。

更新1:这是源数据的示例。实际表具有数百条记录和80个群集。

CREATE TABLE dbo.example (
    iUnity      int NOT NULL,
    Cluster     char(2) NOT NULL,
    fValue      float NOT NULL
)

15  A1      150
17  A1      170
21  B2      210
23  B2      230
71  C3      710
Run Code Online (Sandbox Code Playgroud)

这是计算顺序的CTE:

WITH cteSequencing AS (
    SELECT
        iUnity,Cluster
        ,fValue as fValueOriginal
        ,row_number() OVER (PARTITION BY Cluster ORDER BY fValueOriginal) as iSequence
    FROM dbo.example
)
Run Code Online (Sandbox Code Playgroud)

如果将基于fValueOriginal计算fValueAjusted,则查询将类似于:

SELECT
    iUnity,Cluster,fValueOriginal
    ,(
        lag(fValue,1,fValue) OVER (PARTITION BY Cluster ORDER BY iSequence)
        + fValueOriginal
    ) / 2 as fValueAjusted
FROM cteSequencing
Run Code Online (Sandbox Code Playgroud)

但是,必须基于先前记录的fValueAjusted计算一条记录的fValueAjusted。就像这样:

SELECT
    iUnity,Cluster,fValueOriginal
    ,(
        lag(fValueAjusted,1,fValueOriginal) OVER (PARTITION BY Cluster ORDER BY iSequence)
        + fValueOriginal
    ) / 2 as fValueAjusted
FROM cteSequencing
Run Code Online (Sandbox Code Playgroud)

当然,fValueAjusted在执行时不可用。LAG()必须递归进行,计算记录的列,然后提供此列供下一个记录使用。

Ale*_*lex 6

更新:原始答案不正确

这是正确的:

该代码使用递归CTE

CREATE TABLE #example (
    iUnity      int NOT NULL,
    Cluster     char(2) NOT NULL,
    fValue      float NOT NULL
)
INSERT INTO #example
VALUES
( 15,  'A1',      150 ),
( 16,  'A1',      170 ),
( 17,  'A1',      190 ),
( 18,  'A1',      210 ),
( 21,  'B2',      210 ),
( 23,  'B2',      230 ),
( 71,  'C3',      710 )

WITH cteSequencing AS (
    -- Get Values Order
    SELECT iUnity, Cluster, fValue, fValue AS fValueAjusted,
        ROW_NUMBER() OVER (PARTITION BY Cluster ORDER BY fValue) AS iSequence
    FROM #example
),
Recursion AS(
    -- Anchor - the first value in clusters
    SELECT iUnity, Cluster, fValue, fValueAjusted, iSequence
    FROM cteSequencing
    WHERE iSequence = 1
    UNION ALL
    -- Calculate next value based on the previous
    SELECT b.iUnity As iUnity, b.Cluster, b.fValue,
        ( a.fValueAjusted + b.fValue ) / 2 AS fValueAjusted,
        b.iSequence
    FROM Recursion AS a
        INNER JOIN cteSequencing AS b ON a.iSequence + 1 = b.iSequence AND a.Cluster = b.Cluster
)
SELECT * FROM Recursion ORDER BY Cluster, fValue

-- Manually check results
SELECT ( 150 + 170 ) / 2
SELECT ( 190 + 160 ) / 2 
SELECT ( 190 + 170 ) / 2
Run Code Online (Sandbox Code Playgroud)

输出:

iUnity      Cluster fValue                 fValueAjusted          iSequence
----------- ------- ---------------------- ---------------------- --------------------
15          A1      150                    150                    1
16          A1      170                    160                    2
17          A1      190                    175                    3
18          A1      210                    192.5                  4
21          B2      210                    210                    1
23          B2      230                    220                    2
71          C3      710                    710                    1
Run Code Online (Sandbox Code Playgroud)

更新资料

如果遇到

语句完成之前已用尽最大递归100

错误,然后使用OPTION (MAXRECURSION xxx)设置更大的递归限制,最高为32,767。