Vig*_*esh 0 python dictionary list
我有嵌套列表,看起来像这样
my_list = [[1,'raj','CSE'],[2,'kumar','MECH'],[3,'Nisha','ECE']]
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由于我需要将其导出为CSV,我想将其转换为字典.我的输出应该是这样的.
my_dict = {'id':[1,2,3],'Name':['raj','kumar','Nisha'],'Course':['CSE','MECH','ECE']}
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我怎么能实现这个???
cs9*_*s95 13
轻松完成zip:
l = [[1,'raj','CSE'],[2,'kumar','MECH'],[3,'Nisha','ECE']]
d = dict(zip(['Id', 'Name', 'Course'], map(list, (zip(*l)))))
d
# {'Course': ['CSE', 'MECH', 'ECE'],
# 'Id': [1, 2, 3],
# 'Name': ['raj', 'kumar', 'Nisha']}
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由于你想在将它保存到csv之前首先将它转换为dict,我假设你使用pandas(否则它更容易以现有的形式保存它).这很容易做到:
df = pd.DataFrame(d) # `d` is from the code snippet above.
df
Course Id Name
0 CSE 1 raj
1 MECH 2 kumar
2 ECE 3 Nisha
df.to_csv('test.csv')
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另外,如果你不希望使用大熊猫,只是这样做:
l = [[1,'raj','CSE'],[2,'kumar','MECH'],[3,'Nisha','ECE']]
with open('test.csv', 'w') as f:
writer = csv.writer(f)
writer.writerow(['Id', 'Name', 'Course'])
writer.writerows(l)
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在这种情况下,您不需要转换为字典.
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