Char-array到int

Question

我有一个阵列 char input[11] = {'0','2','7', '-','1','1','2', ,'0','0','9','5'};

如何将输入[0,1,2]转换为int one = 27输入[3,4,5,6] int two = -112并输入[7,8,9,10]为int three = 95？

是的,JNK

Answer 1

您可以使用组合strncpy()来提取字符范围并将atoi()其转换为整数(或者阅读此问题以获取将字符串转换为int的更多方法).

int extract(char *input, int from, int length) {
  char temp[length+1] = { 0 };
  strncpy(temp, input+from, length);
  return atoi(temp);
}

int main() {
  char input[11] = {'0','2','7','-','1','1','2','0','0','9','5'};
  cout << "Heading: " << extract(input, 0, 3) << endl;
  cout << "Pitch:   " << extract(input, 3, 4) << endl;
  cout << "Roll:    " << extract(input, 7, 4) << endl;
}

输出

Heading: 27
Pitch:   -112
Roll:    95

http://ideone.com/SUutl