比较2个字符串,减去相同的字符并返回新值

Question

我有两个字符串,它可能多于两个可能是5或6

 $a =  2012-05-18 usr abc removed device id=858 sn=abc cmmac=000 drumac=123
 $b =  2012-05-18 usr abc removed device id=858 sn=abc cmmac=000 drumac=12352015-03-26 usr mabdel001c removed device id=814 sn=abcd cmmac=1234 drumac=000

我需要帮助我需要一个函数或任何方式,当我将$ a与$ b进行比较时,它应该只返回我下面的字符串

$remaining = '2015-03-26 usr mabdel001c removed device id=814 sn=abcd cmmac=1234 drumac=000';

我试过这个功能没有运气 if (strcmp($var1, $var2) === 0) {

Answer 1

你想到它的方式似乎并不明显,但str_replace应该为此工作.

$remaining = str_replace($a, '', $b);

如果$a在发现$b然后$remaining将$b用字符$a从它删除,否则$remaining将是不变的值$b.

Answer 2

您可以使用str_replace并替换为空：

$a =  "2012-05-18 usr abc removed device id=858 sn=abc cmmac=000 drumac=123";
$b =  "2012-05-18 usr abc removed device id=858 sn=abc cmmac=000 drumac=12352015-03-26 usr mabdel001c removed device id=814 sn=abcd cmmac=1234 drumac=000";

Echo str_replace($a, "", $b);

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