将k列重新整形为2列,表示k个变量值的连续对

Question

我有一个这样的数据框:

id y1 y2 y3 y4  
--+--+--+--+--
a |12|13|14|  
b |12|18|  |
c |13|  |  |
d |13|14|15|16  

我想以这样的方式重塑,我以两列结束.以上示例将变为:

id from to  
--+----+--- 
a |12  |13  
a |13  |14  
a |14  |
b |12  |18
b |18  |  
c |13  |
d |13  |14  
d |14  |15  
d |15  |16  

每个id年份都有一个'from'和'to'.
有人知道一个简单的方法吗？我试过用reshape2.我还看了将多列合并到整洁的数据中,但我认为我的情况有所不同.

Answer 1

您可以使用lapply循环对列并将rbind它们联合起来:

do.call(rbind,
        lapply(2:(length(df)-1), 
               function(x) setNames(df[!is.na(df[,x]),c(1,x,x+1)], 
                                    c("id", "from", "to"))))
   id from to
1   a   12 13
2   b   12 18
3   c   13 NA
4   d   13 14
11  a   13 14
21  b   18 NA
41  d   14 15
12  a   14 NA
42  d   15 16

Answer 2

解决方案使用dplyr和tidyr.dt2是最终的输出.

# Create example data frame
dt <- data.frame(id = c("a", "b", "c", "d"),
                 y1 = c(12, 12, 13, 13),
                 y2 = c(13, 18, NA, 14),
                 y3 = c(14, NA, NA, 15),
                 y4 = c(NA, NA, NA, 16),
                 stringsAsFactors = FALSE)

# Load packages
library(dplyr)
library(tidyr)

# Process the data
dt2 <- dt %>%
  gather(STEP, from, -id) %>%
  drop_na(from) %>%
  arrange(id, STEP) %>%
  group_by(id) %>%
  mutate(to = lead(from)) %>%
  select(-STEP)