我正在尝试进行以下选择:
select * from urlpath where substring(urlpathpath, 3, len(urlpathpath))
not in (select accessuserpassword from accessuser where accessuserparentid = 257)
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我收到错误:
Cannot resolve the collation conflict between
"SQL_Latin1_General_CP1_CI_AI" and
"SQL_Latin1_General_CP1_CI_AS" in the equal to operation.
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有谁知道我如何作为整理,或允许我匹配这种情况的东西?
感谢名单
小智 6
您甚至可以对查询进行整理以使用该查询创建新表,例如:
SELECT
*
INTO
#TempTable
FROM
View_total
WHERE
YEAR(ValidFrom) <= 2007
AND YEAR(ValidTo)>= 2007
AND Id_Product = '001'
AND ProductLine COLLATE DATABASE_DEFAULT IN (SELECT Product FROM #TempAUX)
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COLLATE DATABASE_DEFAULT 导致 COLLATE 子句继承当前数据库的排序规则,消除两者之间的差异
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