如何使用lodash递归地从JSON中删除空对象

Question

var template = {
    personal: {},
    education: {},
    certificate: [{"test": "Test"}, {}, {}],
    experience: []
}

removeEmptyObj(template);

function removeEmptyObj(obj)
for (var key in obj) {
    console.log("Foor Loop" + key + " " + obj[key]);
    if (_.isObject(obj[key]) && !_.isEmpty(obj[key])) {
        console.log("Second Loop Object:::" + key + " " + obj[key]);
        removeEmptyObj(obj[key]);
    }
    if (_.isEmpty(obj[key])) {
        console.log("Delete Object:::" + key + " " + obj[key]);
        obj = _.omitBy(obj, _.isEmpty);
    }
}
console.log(obj);
return obj;
}

电流输出是: {certificate: [{"test": "Test"}, {}, {}]}

期望的输出: {certificate: [{"test": "Test"}]}

这有什么不对,你的帮助欣赏:)

Answer 1

您可以_.transform()将对象递归到新对象,并在途中清理空对象和数组.

注意:我在结构中添加了更多元素用于演示

var template = {
    personal: {},
    education: {},
    certificate: [{}, {"test": "Test"}, {}, {}, [{}], [{}, 1, []]],
    experience: [[1, 2, [], { 3: [] }]]
};

function clean(el) {
  function internalClean(el) {
    return _.transform(el, function(result, value, key) {
      var isCollection = _.isObject(value);
      var cleaned = isCollection ? internalClean(value) : value;

      if (isCollection && _.isEmpty(cleaned)) {
        return;
      }

      _.isArray(result) ? result.push(cleaned) : (result[key] = cleaned);
    });
  }

  return _.isObject(el) ? internalClean(el) : el;
}

console.log(clean(template));

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