dav*_*dev 16 javascript android cross-platform ios react-native
谢谢你们的回答,
我是React Native的新手,我想创建一个跨平台的应用程序,所以我创建了index.js:
import React from 'react';
import {
Component,
View,
Text,
} from 'react-native';
class ReactApp extends Component {
render() {
return (
<View><Text>Hello world</Text></View>
);
}
}
module.exports = ReactApp;
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然后我从index.ios.js和index.android.js导入了index.js,如下所示:
import { AppRegistry } from 'react-native';
import ReactApp from './index';
AppRegistry.registerComponent('ReactApp', () => ReactApp);
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我认为在此之后它应该工作,但我得到这个错误:
Flo*_*s M 36
在React v0.49之后,你不需要index.ios.js和index.android.js.你只需要index.js:
import {AppRegistry} from 'react-native';
import App from './app/App';
AppRegistry.registerComponent('appMobile', () => App);
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(替换appMobile为您的应用程序的名称)
资料来源:(https://github.com/facebook/react-native/releases/tag/v0.49.0)
从现在开始,新项目只有一个入口点(index.js)
你正在倒退这个.index.ios.js并且index.android.js将始终是默认react-native init项目中的单独入口点.如果你想让它们通过相同的代码库运行index.js,你应该设置它,index.ios.js然后index.android.js导入index.js并注册相同的基本组件index.js.
例如,您可以在此示例ToDo应用程序(此处为Github repo)中查看它是如何完成的.
如果你把index.js你的根文件夹,它会产生冲突index.android.js,并index.ios.js当你不直接引用它.因此,您需要指向导入中的确切路径.请参阅下面的代码.
index.ios.js和index.android.js(相同内容)
import React from 'react';
import { AppRegistry } from 'react-native'
import ReactApp from './index.js'
// Had you placed index.js in another folder like `./app`, you could instead do your import with this shorthand:
// import ReactApp from './app'
AppRegistry.registerComponent('ReactApp', () => ReactApp)
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index.js
// Note: I noticed that you imported Component from the wrong place. That might also be contributing to your issue so I fixed it here.
import React, { Component } from 'react';
import {
View,
Text,
} from 'react-native';
// Unless you are exporting multiple things from a single file, you should just use this.
// It's more idiomatic than using module.exports = ReactApp;
export default class ReactApp extends Component {
render() {
return (
<View><Text>Hello world</Text></View>
);
}
}
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在 iOS AppDelegate.m 中改变这个
jsCodeLocation = [[RCTBundleURLProvider sharedSettings] jsBundleURLForBundleRoot:@"index.ios" fallbackResource:nil];
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到
jsCodeLocation = [[RCTBundleURLProvider sharedSettings] jsBundleURLForBundleRoot:@"index" fallbackResource:nil];
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