我想使用 dplyr 比较分组 data.frame 内的值,并创建一个虚拟变量或类似的变量,指示哪个更大。想不通!
这是一些可重现的代码:
table <- structure(list(species = structure(c(1L, 1L, 1L, 2L, 2L, 2L), .Label = c("Adelophryne adiastola",
"Adelophryne gutturosa"), class = "factor"), scenario = structure(c(3L,
1L, 2L, 3L, 1L, 2L), .Label = c("future1", "future2", "present"
), class = "factor"), amount = c(5L, 3L, 2L, 50L, 60L, 40L)), .Names = c("species",
"scenario", "amount"), class = "data.frame", row.names = c(NA,
-6L))
> table
species scenario amount
1 Adelophryne adiastola present 5
2 Adelophryne adiastola future1 3
3 Adelophryne adiastola future2 2
4 Adelophryne gutturosa present 50
5 Adelophryne gutturosa future1 60
6 Adelophryne gutturosa future2 40
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我会将 df 按 分组species。我想创建一个新列,可以是increase_amount,其中每个“未来”的金额与“现在”进行比较。当值增加时我可以得到 1,当值减少时我可以得到 0。
我一直在尝试使用一个 for 循环来抛出每个物种,但是 df 包含超过 50,000 个物种,并且对于我必须重新执行操作的时间来说花费的时间太长......
有人知道办法吗?多谢!
你可以这样做:
table %>%
group_by(species) %>%
mutate(tmp = amount[scenario == "present"]) %>%
mutate(increase_amount = ifelse(amount > tmp, 1, 0))
# Source: local data frame [6 x 5]
# Groups: species [2]
#
# species scenario amount tmp increase_amount
# <fctr> <fctr> <int> <int> <dbl>
# 1 Adelophryne adiastola present 5 5 0
# 2 Adelophryne adiastola future1 3 5 0
# 3 Adelophryne adiastola future2 2 5 0
# 4 Adelophryne gutturosa present 50 50 0
# 5 Adelophryne gutturosa future1 60 50 1
# 6 Adelophryne gutturosa future2 40 50 0
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