尽管只发送了一个ID,为什么我会收到"预期的单例"错误？

Question

我在模型中添加了一些字段,stock.move然后导入CSV文件以创建一些记录.我查看了所有行,然后逐个创建记录,如下所示:

lot_id = self._get_lot_id(
    n, row, product_id, picking_type_id,
    box_quantity, product_uom_qty
)

move = {
    'auto_lot_name': False,
    'box_quantity': 2,
    'client_order_ref': '581002',
    'date': datetime.datetime(2017, 6, 24, 19, 55, 52, 372648),
    'invoice_state': '2binvoiced',
    'location_dest_id': 9,
    'location_id': 12,
    'name': 'Product name',
    'partner_id': 487,
    'partner_shipping_id': 488,
    'picking_type_id': 2,
    'price_unit': 4.0,
    'pricelist_id': 1,
    'product_code': u'36033',
    'product_id': 3,
    'product_uom': 3,
    'product_uom_qty': 6.0,
    'restrict_lot_id': 12222,   # lot_id
    'tax_id': [(4, 67)]
}

result = self.env['stock.move'].create(move)

如果方法需要,我会创建批次_get_lot_id.如果已经创建了批次,则返回id.这很好用

它非常简单并且可以很好地工作很多次,但有时我会得到以下错误,尽管我restrict_lot_id只在字典中填充了一个id.看起来它正在追加前一个循环的批次ID.怎么可能？我的数据库坏了吗？

File "/[ ... ]/import_moves/models/stock_picking_import_wizard.py", line 129, in _generate_moves_from_csv
    result = self.env['stock.move'].create(move)
  File "/[ ... ]/openerp/api.py", line 266, in wrapper
    return new_api(self, *args, **kwargs)
  File "/[ ... ]/openerp/api.py", line 508, in new_api
    result = method(self._model, cr, uid, *args, **old_kwargs)
  File "/[ ... ]/stock/stock.py", line 1993, in create
    res = super(stock_move, self).create(cr, uid, vals, context=context)
  File "/[ ... ]/openerp/api.py", line 268, in wrapper
    return old_api(self, *args, **kwargs)
  File "/[ ... ]/openerp/api.py", line 372, in old_api
    result = method(recs, *args, **kwargs)
  File "/[ ... ]/connector/producer.py", line 48, in create     ##> strange because this module is not installed
    record_id = create_original(self, vals)
  File "/[ ... ]/openerp/api.py", line 266, in wrapper
    return new_api(self, *args, **kwargs)
  File "/[ ... ]/openerp/models.py", line 4126, in create
    record = self.browse(self._create(old_vals))
  File "/[ ... ]/openerp/api.py", line 266, in wrapper
    return new_api(self, *args, **kwargs)
  File "/[ ... ]/openerp/api.py", line 508, in new_api
    result = method(self._model, cr, uid, *args, **old_kwargs)
  File "/[ ... ]/openerp/models.py", line 4323, in _create
    recs._validate_fields(vals)
  File "/[ ... ]/openerp/api.py", line 266, in wrapper
    return new_api(self, *args, **kwargs)
  File "/[ ... ]/openerp/models.py", line 1285, in _validate_fields
    raise ValidationError("Error while validating constraint\n\n%s" % tools.ustr(e))
ValidationError: ('ValidateError', u'Error while validating constraint\n\nValueError\nExpected singleton: stock.production.lot(12286, 12287)')

我还验证了id到达模块中的原始create函数内部stock.这对我没有任何意义.怎么了？

我刚检查过,如果我总是创造它,它运作良好.所以_get_lot_id我在这里展示的方法有些不对劲

def _get_lot_id(self, n, row, product_id,
                picking_type_id, box_quantity, product_uom_qty):
    lot_id_name = row.get('lot_id_name', False)
    if lot_id_name != '':
        if picking_type_id == STOCK_PICKING_TYPE_OUT:
            lot_ids = self.env['stock.production.lot'].search([
                ('product_id', '=', product_id.id),
                ('name', '=', lot_id_name)
            ])
            if len(lot_ids) == 0:
                try:
                    lot_id = self.env['stock.production.lot'].create({
                        'name': lot_id_name,
                        'product_id': product_id.id,
                    })                
                except Exception:
                    raise Warning(_('The lot could not be created. '
                                    '\nROW: %s') % n)
                return lot_id.ensure_one().id
            if len(lot_ids) == 1:
                return lot_ids[0].id
            else:
                raise Warning(_('ERROR\nThere is more than one lot with the same name for that product.'
                                '\nROW: %s') % n)                
        elif picking_type_id == STOCK_PICKING_TYPE_IN:
            lot_ids = self.env['stock.production.lot'].search([
                ('product_id', '=', product_id.id),
                ('name', '=', lot_id_name)
            ])
            if len(lot_ids) == 1:
                return lot_ids[0].id
            try:
                lot_id = self.env['stock.production.lot'].create({
                    'name': lot_id_name,
                    'product_id': product_id.id,
                })
                return lot_id.id
            except Exception:
                raise Warning(_('The lot could not be created. '
                                '\nROW: %s') % n)
    else:
        if picking_type_id == STOCK_PICKING_TYPE_OUT:
            raise Warning(_('The lot is required for outgoing moves. '
                            '\nROW: %s') % n)
        elif picking_type_id == STOCK_PICKING_TYPE_IN:
            # set "auto_lot_name = True"  >> this is set by default, so the lot is automatically created
            return False

Answer 1

我认为问题出在你的一个代码中,确保在注释代码时重启服务器.但是让我解释为什么这个错误可能发生在odoo中,方法中的self是一个记录集,意味着它可以包含一个或多个记录.当你使用装饰器@ api.multi,depends或者约束时,self可以包含多个记录,以避免这种错误,确保你循环自我.

     for rec in self:
               # your code here
               # always access to rec fields not self here

如果您在执行self此操作时不循环,则当记录集只有一条记录时可以正常工作,但是当您有更多记录时,这会让您想要获取some_field的值的记录混乱,这里会出现此错误.

但是当你在这里使用装饰器@ api.one时,你告诉odoo在自己传递一条记录所以单身错误永远不会与api.one一起使用不要使用api.one它不建议用于循环.

检查原始插件中的代码,他们在计算字段中使用几乎循环.

当我学习odoo时,这个错误让我发疯.阅读有关装饰器一和多,以了解差异