读取zip存档中的文本文件

Question

我有zip存档,其中包含一堆纯文本文件.我想解析每个文本文件数据.这是我到目前为止所写的内容:

try {
    final ZipFile zipFile = new ZipFile(chooser.getSelectedFile());
    final Enumeration<? extends ZipEntry> entries = zipFile.entries();
    ZipInputStream zipInput = null;

    while (entries.hasMoreElements()) {
        final ZipEntry zipEntry = entries.nextElement();
        if (!zipEntry.isDirectory()) {
            final String fileName = zipEntry.getName();
            if (fileName.endsWith(".txt")) {
                zipInput = new ZipInputStream(new FileInputStream(fileName));
                final RandomAccessFile rf = new RandomAccessFile(fileName, "r");
                String line;
                while((line = rf.readLine()) != null) {
                    System.out.println(line);
                }
                rf.close();
                zipInput.closeEntry();
            }
        }
    }
    zipFile.close();
}
catch (final IOException ioe) {
    System.err.println("Unhandled exception:");
    ioe.printStackTrace();
    return;
}

我需要一个RandomAccessFile吗？我失去了我拥有ZipInputStream的地步.

Answer 1

不,你不需要RandomAccessFile.首先获取InputStream此zip文件条目的数据:

InputStream input = zipFile.getInputStream(entry);

然后将其包装成InputStreamReader(从二进制到文本解码)和a BufferedReader(一次读取一行):

BufferedReader br = new BufferedReader(new InputStreamReader(input, "UTF-8"));

然后正常读取它的线条.try/finally像往常一样将所有适当的位包装在块中,以关闭所有资源.