dns*_*_nx 5 javascript arrays filter reactjs
我有这段代码,它可以过滤我的数据。我问我,是否有一种方法可以不显式过滤每个字段(id、mandant、zonenlogik...)。也许有一种更流畅的方法可以在所有字段上设置过滤器而无需显式调用它们?
let filteredList = this.state.freights.filter((freight) => {
if (freight.id.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
return freight;
}
if (freight.mandant.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
return freight;
}
if (freight.zonenlogik.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
return freight;
}
if (freight.frachtart_nr.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
return freight;
}
if (freight.transportart_nr.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
return freight;
}
if (freight.spedit_nr.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
return freight;
}
if (freight.spedit2_nr.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
return freight;
}
if (freight.lager_nr.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
return freight;
}
});
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You can fetch the object values using Object.values() and then loop over those to check whether a substring is present in the string and then return the filtered object
let filteredList = this.state.freights.filter((freight) => {
let search = this.state.search.toLowerCase();
var values = Object.values(freight);
var flag = false
values.forEach((val) => {
if(val.toLoweCase().indexOf(search) > -1) {
flag = true;
return;
}
}
if(flag) return freight
});
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