Ale*_* D. 0 c++ multithreading mutex
我在继承的类中使用了互斥,但似乎它不像我预期的那样工作.请看下面的代码:
#include <iostream>
#include <cstdlib>
#include <pthread.h>
// mutex::lock/unlock
#include <iostream> // std::cout
#include <thread> // std::thread
#include <chrono> // std::thread
#include <mutex> // std::mutex
typedef unsigned int UINT32t;
typedef int INT32t;
using namespace std;
class Abstract {
protected:
std::mutex mtx;
};
class Derived: public Abstract
{
public:
void* write( void* result)
{
UINT32t error[1];
UINT32t data = 34;
INT32t length = 0;
static INT32t counter = 0;
cout << "\t before Locking ..." << " in thread" << endl;
mtx.lock();
//critical section
cout << "\t After Create " << ++ counter << " device in thread" << endl;
std::this_thread::sleep_for(1s);
mtx.unlock();
cout << "\t deallocated " << counter << " device in thread" << endl;
pthread_exit(result);
}
};
void* threadTest1( void* result)
{
Derived dev;
dev.write(nullptr);
}
int main()
{
unsigned char byData[1024] = {0};
ssize_t len;
void *status = 0, *status2 = 0;
int result = 0, result2 = 0;
pthread_t pth, pth2;
pthread_create(&pth, NULL, threadTest1, &result);
pthread_create(&pth2, NULL, threadTest1, &result2);
//wait for all kids to complete
pthread_join(pth, &status);
pthread_join(pth2, &status2);
if (status != 0) {
printf("result : %d\n",result);
} else {
printf("thread failed\n");
}
if (status2 != 0) {
printf("result2 : %d\n",result2);
} else {
printf("thread2 failed\n");
}
return -1;
}
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结果是:
*预期有四到五个参数.
before Locking ... in thread
After Create 1 device in thread
before Locking ... in thread
After Create 2 device in thread
deallocated 2 device in thread
deallocated 2 device in thread
thread failed
thread2 failed
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*
所以在这里我们可以看到,在释放互斥锁之前,第二个线程进入临界区.字符串"在线程中创建2个设备后"说明了这一点.如果在解除分配mutex之前涉及临界区,则意味着互斥锁工作错误.
如果您有任何想法请分享.
谢谢