使用不同的名称通过Json.Net进行序列化和反序列化

Question

我正在从如下所示的Web API接收JSON数据：

[
  {
    "id": 1
    "error_message": "An error has occurred!"
  }
]

我将此数据反序列化为以下类型的对象：

public class ErrorDetails
{
    public int Id { get; set; }

    [JsonProperty("error_message")]
    public string ErrorMessage { get; set; }
}

稍后在我的应用程序中，我想再次将ErrorDetails对象序列化为JSON，但使用属性名称ErrorMessage代替error_message。因此结果将如下所示：

[
  {
    "Id": 1
    "ErrorMessage": "An error has occurred!"
  }
]

Is there an easy way I can accomplish this with Json.Net? Perhaps using a custom resolver and some attributes like:

public class ErrorDetails
{
    public int Id { get; set; }

    [SerializeAs("ErrorMessage")]
    [DeserializeAs("error_message")]
    public string ErrorMessage { get; set; }
}

But the resolver doesn't tell me when I'm serializing or deserializing.

Answer 1

您可以使用JsonSerializerSettings，ContractResolver和NamingStrategy。

public class ErrorDetails
{
    public int Id { get; set; }
    public string ErrorMessage { get; set; }
}

var json = "{'Id': 1,'error_message': 'An error has occurred!'}";

对于反序列化，您可以使用SnakeCaseNamingStrategy。

var dezerializerSettings = new JsonSerializerSettings
{
    ContractResolver = new DefaultContractResolver
    {
        NamingStrategy = new SnakeCaseNamingStrategy()
    }
};
var obj = JsonConvert.DeserializeObject<ErrorDetails>(json, dezerializerSettings);

要再次序列化对象，您不必更改，JsonSerializerSettings因为默认情况下将使用属性名称。

var jsonNew = JsonConvert.SerializeObject(obj);

jsonNew =“ {'Id'：1，'ErrorMessage'：'发生错误！'}”

或者，您可以创建合同解析器来决定要使用的名称。然后，您可以决定何时使用反序列化和序列化，以使用pascal案例名称格式还是带下划线的格式。

public class CustomContractResolver : DefaultContractResolver
{
    public bool UseJsonPropertyName { get; }

    public CustomContractResolver(bool useJsonPropertyName)
    {
        UseJsonPropertyName = useJsonPropertyName;
    }

    protected override JsonProperty CreateProperty(MemberInfo member, MemberSerialization memberSerialization)
    {
        var property = base.CreateProperty(member, memberSerialization);
        if (!UseJsonPropertyName)
            property.PropertyName = property.UnderlyingName;

        return property;
    }
}

public class ErrorDetails
{
    public int Id { get; set; }
    [JsonProperty("error_message")]
    public string ErrorMessage { get; set; }
}


var json = "{'Id': 1,'error_message': 'An error has occurred!'}";
var serializerSettings = new JsonSerializerSettings()
{
    ContractResolver = new CustomContractResolver(false)
};
var dezerializerSettings = new JsonSerializerSettings
{
    ContractResolver = new CustomContractResolver(true)
};

var obj = JsonConvert.DeserializeObject<ErrorDetails>(json, dezerializerSettings);
var jsonNew = JsonConvert.SerializeObject(obj, serializerSettings);

jsonNew =“ {'Id'：1，'ErrorMessage'：'发生错误！'}”