通过本机反应传递复选框值以显示/隐藏密码

Question

我正在使用 Firebase auth 我想添加一个复选框，它将在密码文本框中显示密码并在再次单击时隐藏它

如何传递复选框值以显示/隐藏密码？

这是我的登录页面代码：

export default class Login extends Component {
    constructor(props) {
        super(props)
        this.state = {
            email: '',
            password: '',
            response: ''
        }
        this.signUp = this.signUp.bind(this)
        this.login = this.login.bind(this)
    }

    async signUp() {
        try {
            await firebase.auth().createUserWithEmailAndPassword(this.state.email, this.state.password)
            this.setState({
                response: 'Account Created!'
            })
            setTimeout(() => {
                this.props.navigator.push({
                    id: 'App'
                })
            }, 500)
        } catch (error) {
            this.setState({
                response: error.toString()
            })
        }
    }
    async login() {
        try {
            await firebase.auth().signInWithEmailAndPassword(this.state.email, this.state.password)
            this.setState({
                response: 'user login in'
            })

            setTimeout(() => {
                this.props.navigator.push({
                    id: 'App'
                })
            })

        } catch (error) {
            this.setState({
                response: error.toString()
            })
        }
    }

    render() {
        return (
            <View style={styles.container}>
                <View style={styles.containerInputes}>
                    <TextInput
                        placeholderTextColor="gray"
                        placeholder="Email"
                        style={styles.inputText}
                        onChangeText={(email) => this.setState({ email })}
                    />
                    <TextInput
                        placeholderTextColor="gray"
                        placeholder="Password"
                        style={styles.inputText}
                        password={true}
                        secureTextEntry={true}
                        onChangeText={(password) => this.setState({ password })}
                    />
                </View>
                <TouchableHighlight
                    onPress={this.login}
                    style={[styles.loginButton, styles.button]}
                >
                    <Text
                        style={styles.textButton}
                    >Login</Text>
                </TouchableHighlight>
                <TouchableHighlight
                    onPress={this.signUp}
                    style={[styles.loginButton, styles.button]}
                >
                    <Text
                        style={styles.textButton}
                    >Signup</Text>
                </TouchableHighlight>
            </View>
        )
    }
}

Answer 1

import React, {useState} from 'react';
import {TextInput} from 'react-native';

import Icon from 'react-native-vector-icons/FontAwesome5';

const [hidePass, setHidePass] = useState(true);
    
    <TextInput
              placeholder="Old password"
              autoCompleteType="password"
              secureTextEntry={hidePass ? true : false}
            />
            <Icon
              name={hidePass ? 'eye-slash' : 'eye'}
              size={15}
              color="grey"
              onPress={() => setHidePass(!hidePass)}
            />

Answer 2

一种方法是设置像 showPassword 这样的状态变量，并在选中复选框时切换它。像这样：

import React, { Component } from 'react';
import {
  AppRegistry,
  Text,
  View, 
  TextInput,
  Switch
} from 'react-native';

export default class DemoProject extends Component {
  constructor(props) {
    super(props);
    this.toggleSwitch = this.toggleSwitch.bind(this);
    this.state = {
      showPassword: true,
    }
  }

  toggleSwitch() {
    this.setState({ showPassword: !this.state.showPassword });
  }

  render() {
    return (
      <View>
        <TextInput
          placeholderTextColor="gray"
          placeholder="Password"
          secureTextEntry={this.state.showPassword}
          onChangeText={(password) => this.setState({ password })}
        />
        <Switch
          onValueChange={this.toggleSwitch}
          value={!this.state.showPassword}
        /> 
        <Text>Show</Text>
      </View>
    )
  }
}

AppRegistry.registerComponent('DemoProject', () => DemoProject);

注意：如果您设置了密码道具，这将不起作用！！！

所以只需使用常规TextInput并使用secureTextEntry道具。

Answer 3

这是我的做法

const LoginScreen = props => {
  const [icon, setIcon] = useState("eye-off")
  const [hidePassword, setHidePassword] = useState(true)

  _changeIcon = () => {
    icon !== "eye-off"
      ? (setIcon("eye-off"), setHidePassword(false))
      : (setIcon("eye"), setHidePassword(true))
  }

我使用本机基础作为文本输入

 <Input
              secureTextEntry={hidePassword}
              placeholder="Password"
              placeholderTextColor={palette.gray}
            />
            <Icon name={icon} size={20} onPress={() => _changeIcon()} />

这将更改单击时的 secureTextEntry