我有一个df,其"产品"列是如下列表:
+----------+---------+--------------------+
|member_srl|click_day| products|
+----------+---------+--------------------+
| 12| 20161223| [2407, 5400021771]|
| 12| 20161226| [7320, 2407]|
| 12| 20170104| [2407]|
| 12| 20170106| [2407]|
| 27| 20170104| [2405, 2407]|
| 28| 20161212| [2407]|
| 28| 20161213| [2407, 100093]|
| 28| 20161215| [1956119]|
| 28| 20161219| [2407, 100093]|
| 28| 20161229| [7905970]|
| 124| 20161011| [5400021771]|
| 6963| 20160101| [103825645]|
| 6963| 20160104|[3000014912, 6626...|
| 6963| 20160111|[99643224, 106032...|
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如何添加列表product_cnt长度的新列products?以及如何过滤df以获得具有给定产品长度条件的指定行?谢谢.
Dav*_*yne 12
Pyspark具有内置功能,可以实现您想要的功能size.http://spark.apache.org/docs/latest/api/python/pyspark.sql.html#pyspark.sql.functions.size.要将其添加为列,您只需在select语句中调用它即可.
from pyspark.sql.functions import size
countdf = df.select('*',size('products').alias('product_cnt'))
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过滤与@ titiro89描述的完全一样.此外,您可以使用size过滤器中的功能.这将允许您以下列方式绕过添加额外列(如果您希望这样做).
filterdf = df.filter(size('products')==given_products_length)
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第一个问题:
如何添加新列product_cnt属于产品长度列表?
>>> a = [(12,20161223, [2407,5400021771]),(12,20161226,[7320,2407])]
>>> df = spark.createDataFrame(a,
["member_srl","click_day","products"])
>>> df.show()
+----------+---------+------------------+
|member_srl|click_day| products|
+----------+---------+------------------+
| 12| 20161223|[2407, 5400021771]|
| 12| 20161226|[7320, 2407, 4344]|
+----------+---------+------------------+
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您可以在此处找到类似的示例
>>> from pyspark.sql.types import IntegerType
>>> from pyspark.sql.functions import udf
>>> slen = udf(lambda s: len(s), IntegerType())
>>> df2 = df.withColumn("product_cnt", slen(df.products))
>>> df2.show()
+----------+---------+------------------+-----------+
|member_srl|click_day| products|product_cnt|
+----------+---------+------------------+-----------+
| 12| 20161223|[2407, 5400021771]| 2|
| 12| 20161226|[7320, 2407, 4344]| 3|
+----------+---------+------------------+-----------+
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第二个问题:
以及如何过滤df以获取给定产品长度条件的指定行?
>>> givenLength = 2
>>> df3 = df2.filter(df2.product_cnt==givenLength)
>>> df3.show()
+----------+---------+------------------+-----------+
|member_srl|click_day| products|product_cnt|
+----------+---------+------------------+-----------+
| 12| 20161223|[2407, 5400021771]| 2|
+----------+---------+------------------+-----------+
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