Ansible docker_container 模块环境文件

Question

我对 ansible (v2.3) 的 docker_container 模块有疑问。当我尝试传递env_file剧本中的属性时，出现错误：no such file or directory

---
- hosts: preprod-api
  become: yes
  gather_facts: true
  tasks:
    - name: test configuration
      docker_container:
        name: "backend"
        image: "backend"
        state: started
        exposed_ports:
          - 80
        volumes:
          - /opt/application/i99/current/logs
        user: ansible
        env_file: 
          - "/opt/application/i99/current/backend/backend-PreProd-config.list"

我尝试使用 ansible 服务器上存在的一个文件和目标服务器上存在的一个文件，得到相同的结果。

这是错误：

`fatal: [my_hostname]: FAILED! => {"changed": false, "failed": true, "module_stderr": "Shared connection to my_hostname closed.\r\n", 
"module_stdout": "Traceback (most recent call last):
    File \"/tmp/ansible_rySqS2/ansible_module_docker_container.py\", 
    line 2036, in <module>    main() File \"/tmp/ansible_rySqS2/ansible_module_docker_container.py\", 
    line 2029, in main\r\n    cm = ContainerManager(client)  File \"/tmp/ansible_rySqS2/ansible_module_docker_container.py\", 
    line 1668, in __init__\r\n    self.parameters = TaskParameters(client)\r\n  File \"/tmp/ansible_rySqS2/ansible_module_docker_container.py\", 
    line 784, in __init__\r\n    self.env = self._get_environment()\r\n  File \"/tmp/ansible_rySqS2/ansible_module_docker_container.py\", 
    line 1134, in _get_environment\r\n    parsed_env_file = utils.parse_env_file(self.env_file)\r\n  File \"/usr/lib/python2.7/site-packages/docker/utils/utils.py\", 
    line 961, in parse_env_file with open(env_file, 'r') as f:\r\nIOError: [Errno 2] No such file or directory: \"['/path/to/my/file/that/exist/backend-PreProd-config.env']\"\r\n", "msg": "MODULE FAILURE", "rc": 0}`

所以我的问题是，如何传递 env 文件？

Answer 1

所以我发现了问题。首先语法是：

env_file: /local/dir/some/file.env

该文件必须位于目标服务器上，并且第一个字符中不包含空行或空格。